首先,我要感谢这个网站,它帮了我很多。所以,我想做一个按钮/开关,当它被按下时,它传递一个值"1"到另一个页面,当它没有被按下(默认),它传递值"0"。我已经有一个代码,我与本网站和youtube的用户的帮助下:
<script type="text/javascript">
function onoffalarm(){
var onof = document.getElementById('onof');
var switchonoff = document.getElementById('switchonoff');
if(onof.style.display=="block")
{
onof.style.display= "none";
switchonoff.src= "images/buttonOFF.png";
switchonoff.title= "Turn On";
window.location.href="led.php?value=0";
}else{
onof.style.display="block";
switchonoff.src= "images/buttonON2.png";
switchonoff.title= "Turn OFF";
window.location.href="led.php?value=1";
}
}
<img id="switchonoff" onmousedown= "onoffalarm()" src="images/ButtonOFF.png" width="217" height="217" alt="" title="Turn On">
<div id="onof">
</div>
在这段代码中,传递给"led.php"的唯一值是"1",但正如我所说,我希望它在按下时传递值1,在未按下时传递值0。另外,我还想知道如何保存按钮状态,当我刷新时,例如。我该怎么做呢?
看到
https://www.youtube.com/watch?v=A-3BxXdISG8如何让JS变量在页面刷新后保留值?
如何在php中获取javascript变量值
Thanks for the help
您可以在JavaScript中使用cookie来存储在浏览器范围内可用的变量。刷新页面或关闭页面时,这些变量不会丢失。只有当用户清除cookie或cookie过期时才会删除。
function setCookie(cname, cvalue, exdays) {
var d = new Date();
d.setTime(d.getTime()+(exdays*24*60*60*1000));
var expires = "expires="+d.toGMTString();
document.cookie = cname + "=" + cvalue + "; " + expires;
}
setCookie("state", 0, 30);
setCookie(nameOfCookie, valueOfCookie, expiryInDays)
你也可以取。
function getCookie(cname) {
var name = cname + "=";
var ca = document.cookie.split(';');
for(var i=0; i<ca.length; i++) {
var c = ca[i].trim();
if (c.indexOf(name)==0)
return c.substring(name.length,c.length);
}
return "";
}
var cookieState = getCookie("state");
getCookie (nameOfCookie)
希望有帮助。