两个链接的php标记相同's "href"属性，输出两个不同的html - Same php markup of two link's "href" attribute, is outputting two different html

Same php markup of two link's "href" attribute, is outputting two different html

php模板-

"home-pg-feed-video" => 
    "<div class='"row home-pg-feed-item pl0 pr0 ml0 mr0'" data-type='"video'">" .
        "<div class='"col-lg-4 col-xs-4 pl0'">" .
            "<a href='"/clinical-dialogue.php?v={{ url }}'"><img src='"{{ thumb-sm }}'" alt='"img'"/></a>" .
        "</div>" .
        "<div class='"col-lg-8 col-xs-8 pr0 '">" .
            "<h4 class='"mb5'">{{ title }}</h4>" .
            "<a href='"/clinical-dialogue.php?v={{ url }}'" class='"watch-link'">Watch the video</a>" .
            "<p>{{ summary }}</p>" .
        "</div>" .
    "</div>"

带有"img"标签的链接正确输出-

<a href="/clinical-dialogue.php?v=Dirk_Arnold_Patient_Selection_3rd_Line_&amp;_Sequencing_Final_Branded-video.php"><img src="images/vid_thumbs/sm/Dirk_Arnold_Branded.png" alt="img"></a>

但是"观看视频"的第二个链接输出-

<a href="/clinical-dialogue.php?v={{ url }}" class="watch-link">Watch the video</a>

我使用模板

的标记

<div class="col-lg-8 col-xs-8 col-lg-feed">
                    <h3 class="feed-name mt0">Featured Clinical Dialogue</h3>
                    <?php
                        for($i = 0; $i < count($featureData); $i++){
                            $item = $featureData[$i];
                            if($item["type"] === "video"){
                                $template = $templates["home-pg-feed-video"];
                                $html = $template;
                                foreach($item as $key => $value){
                                    if($key == "topics") {
                                            $value = implode(", ", $value);
                                        }   
                                        $html = preg_replace("/{{ " . $key . " }}/", $value, $html, 1);
                                }
                                echo $html;
                            }
                        }
                    ?>
                </div>

您的preg_replace行中有"1"，这限制了匹配的数量(即:"url")到1。使用'-1'表示没有限制。

$html = preg_replace("/{{ " . $key . " }}/", $value, $html, -1);

或

$html = preg_replace("/{{ " . $key . " }}/", $value, $html);

但是在您的情况下，不需要regex。使用str_replace，因为它更快:

$html = str_replace("{{ " . $key . " }}", $value, $html);