如何在php中减去两个没有星期天的日期 - How to subtract two dates without sunday in php

How to subtract two dates without sunday in php

本文关键字：两个星期天日期 php | 更新日期: 2023-09-27

我想用php或cakephp函数减去日期，示例：

$date1 = '2016-05-19';
$date2 = '2016-05-23';

我想减去没有星期日的日期，从例子中我想要的结果是3，而不是4，因为4-1（星期日），

我已经尝试使用新的Datetime php，如以下代码，

$receipt_date   = new DateTime($air_way_bill['AirWayBill']['receive_date']);
$date           = new DateTime($air_way_bill['AirWayBill']['date']);
$difference     = $receipt_date->diff($date);

但是结果是4，我怎么能用星期天减去这个范围？有什么步骤或方法可以做到我的意思吗？

提前感谢。。。

【结案】：

正确答案：

// ============================= 1 ==================== //
$receipt_date   = new DateTime('2016-05-19');
$date           = new DateTime('2016-05-23');
$difference     = $receipt_date->diff($date);
$daterange = new DatePeriod($receipt_date, new DateInterval('P1D'), $date);
$count = 0;
foreach($daterange as $date){
    if(!($date->format("w"))) {
        $count++;
    }
}
echo ($difference->days)-$count;

//========================================//

// ============================= 2 ==================== //
function getSubtrackedDayCountWithoutSundaysButWithAllOtherDaysUsingDateTimeFunctions($startDate, $endDate)
{
    $days = $startDate->diff($endDate, true)->days;
    $sundays = intval($days / 7) + ($startDate->format('N') + $days % 7 >= 7);
    return intval($days)-Sundays;

}

//=================================================//

//==========================这是我的实验================//

        $date = date('Y-m-d', strtotime($air_way_bill['AirWayBill']['date']));
        $receive_date = date('Y-m-d', strtotime($air_way_bill['AirWayBill']['receive_date']));
        $date_diff = round(abs(strtotime($receive_date) - strtotime($date)) / 86400);
        $weeks  = round(abs(strtotime($receive_date) - strtotime($date)) / (86400 * 7));
         echo $date_diff - $weeks;

//=================================================//

非常感谢。。。

您可以找到总天数，然后找到该范围内的星期日数。最后从总天数中减少这些天数：

<?php    
$receipt_date   = new DateTime('2016-05-19');
$date           = new DateTime('2016-05-23');
$difference     = $receipt_date->diff($date);
$daterange = new DatePeriod($receipt_date, new DateInterval('P1D'), $date);
$count = 0;
foreach($daterange as $date){
    if(!($date->format("w"))) {
        $count++;
    }
}
echo ($difference->days)-$count;

演示

我编写了一个函数来满足您的要求。

function getSubtrackedDayCountWithoutSundaysButWithAllOtherDaysUsingDateTimeFunctions($startDate, $endDate)
{
    $days = $startDate->diff($endDate, true)->days;
    $sundays = intval($days / 7) + ($startDate->format('N') + $days % 7 >= 7);
    return intval($days)-$sundays;

}