推特引导模式不张贴通过php


twitter bootstrap modal not posting via php

我是一个完全的新手,遇到了障碍。我正在使用twitter引导,我试图通过php发布一个形式模式到mysql服务器。下面是我的代码:

HTML (index . HTML):

<div id="myModal" class="modal hide fade" tabindex="-1" role="dialog" aria-labelledby="ModalLabel" aria-hidden="true">
  <div class="modal-header">
    <button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button>
    <h3 id="ModalLabel">****</h3>
  </div>
  <div class="modal-body">
    <form id="modal-form" accept-charset="UTF-8" method="POST" action="submitform.php" data-remote="true" >
      <p>Give us your email, and we'll send you an invitation</p>
      <fieldset>
    <input type="text" name="email" id="email" class="reqInput" placeholder="Email Address">
    <input type="text" name="name" id="name" class="reqInput" placeholder="Full Name">
    <input type="text" name="company" id="company" class="reqInput" placeholder="Company">
    <input type="text" name="title" id="title" class="reqInput" placeholder="Title">
      </fieldset>
  </div>
  <div class="modal-footer">
    <button class="btn" data-dismiss="modal" aria-hidden="true">Close</button>
    <a id="modal-form-submit" type="submit" name="submit" class="btn btn-primary" href"#">Submit</a>
  </div>
</form>
</div>
PHP (submitform.php):

<?php
$host="localhost"; // Host name 
$username="***"; // Mysql username 
$password="***"; // Mysql password 
$db_name="users"; // Database name 
$tbl_name="userRequests"; // Table name
// Connect to server and select databse.
$con = mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB");
// username and password sent from form 
$name=$_POST['name']; 
$company=$_POST['company'];
$email=$_POST['email'];
$title=$_POST['title'];
if(strlen($name) > 1 && strpos($email, "@")){
// To protect MySQL injection (more detail about MySQL injection)
$name = mysql_real_escape_string(stripslashes($name));
$company = mysql_real_escape_string(stripslashes($company));
$email = mysql_real_escape_string(stripslashes($email));
$title = mysql_real_escape_string(stripslashes($title));
$sql="INSERT INTO $tbl_name (FullName, Company, Email, Title) VALUES ('$name', '$company', '$email', '$title')";
exit;
}
?>

我正在检查Charles,奇怪的是,我甚至没有看到发送了大约45秒的POST,直到我得到一个本地命令错误。因此,我不知道该如何继续。我肯定我错过了一些东西。如有任何建议,不胜感激。

注:我知道SQL数据库是工作,因为它连接到旧的php网站,我要取代。字段是文本等。问题是我上面的代码。

您的if(strlen(....缺少关闭的}

更新:HTML

<div id="myModal" class="modal hide fade" tabindex="-1" role="dialog" aria-labelledby="ModalLabel" aria-hidden="true">
  <div class="modal-header">
    <button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button>
    <h3 id="ModalLabel">****</h3>
  </div>
  <div class="modal-body">
    <form id="modal-form" accept-charset="UTF-8" method="POST" action="submitform.php" data-remote="true" >
      <p>Give us your email, and we'll send you an invitation</p>
      <fieldset>
    <input type="text" name="email" id="email" class="reqInput" placeholder="Email Address">
    <input type="text" name="name" id="name" class="reqInput" placeholder="Full Name">
    <input type="text" name="company" id="company" class="reqInput" placeholder="Company">
    <input type="text" name="title" id="title" class="reqInput" placeholder="Title">
      </fieldset>
  </div>
  <div class="modal-footer">
    <button class="btn" data-dismiss="modal" aria-hidden="true">Close</button>
    <input id="modal-form-submit" type="submit" name="submit" class="btn btn-primary" href"#" value="Submit"/>
  </div>
</form>
</div>

你不能让<a>标签有一个输入类型。这将发布您的代码。为什么PHP文件中有exit; ?

我认为问题出在提交按钮上,而不是

<a id="modal-form-submit" type="submit" name="submit" class="btn btn-primary" href"#">Submit</a>
使用

<input type="submit" id="modal-form-submit" name="submit" class="btn btn-primary" />