PHP循环遍历两个数组来查找匹配的键和值 - php loop through 2 arrays to find keys and values that match

php loop through 2 arrays to find keys and values that match

我有以下数组名为investmentprogramcriteria和companyinvestmentprofile:

Array
(
[0] => Array
    (
        [investmentprogramcriteriaID] => 20
        [investmentprogramID] => 21
        [criteriaID] => 59
        [criteriaIsMatchedIf] => 1
    )
[1] => Array
    (
        [investmentprogramcriteriaID] => 21
        [investmentprogramID] => 21
        [criteriaID] => 57
        [criteriaIsMatchedIf] => 1
    )
)

Array
(
[0] => Array
    (
        [investmentprofileID] => 1
        [companyID] => 27
        [criteriaID] => 54
        [investmentprofileCriteriaAnswer] => 1
    )
[1] => Array
    (
        [investmentprofileID] => 2
        [companyID] => 27
        [criteriaID] => 57
        [investmentprofileCriteriaAnswer] => 0
    )
[2] => Array
    (
        [investmentprofileID] => 3
        [companyID] => 27
        [criteriaID] => 58
        [investmentprofileCriteriaAnswer] => 0
    )
[3] => Array
    (
        [investmentprofileID] => 4
        [companyID] => 27
        [criteriaID] => 59
        [investmentprofileCriteriaAnswer] => 1
    )
)

如果第一个数组中的最后两个key AND THEIR VALUES在第二个数组中找到，代码应该返回match，

返回not match。

我尝试用数组函数来解决这个问题，但没有任何工作，现在我试图用php来解决它，但到目前为止还没有运气。

我正在尝试:

foreach ($investmentprogramscriteria as $programcriteria) {
    //foreach($companyInvestmentProfil as $profile) {
        if (($programcriteria['criteriaID'] == $companyInvestmentProfil[$i]['criteriaID']) && ($programcriteria['criteriaIsMatchedIf'] == $companyInvestmentProfil[$i]['investmentprofileCriteriaAnswer']))  {
        $match = "Match";                              
    } else {
       $match = "Not Match";
       continue;
// }                                
}
                        }

最好的方法是使用foreach两次!!

foreach ($investmentprogramscriteria  as $value) {
    foreach ($companyInvestmentProfil as $v) {
        if($v["criteriaID"] == $value["criteriaID"]) echo "match<br>";
        else echo "not Match<br>";
    }    
}

更新

你的代码包含一个bug:

$programcriteria['criteriaID'] == $companyInvestmentProfil[$i]['criteriaID']

变量$i从未定义。你可能想写这样的东西:

// assign keys to $i
foreach ($investmentprogramscriteria as $i => $programcriteria) {
}

在这种情况下，使用下面的array_slice + array_keys方法，带或不带array_intersect_assoc方法应该工作，如果您分别在$programcriteria和$companyInvestmentProfil[$k]数组上使用它们。

你基本上要找的是array_intersect_assoc函数。该函数返回一个数组，其中包含两个数组中存在的所有键值对:

$intersect = array_intersect_assoc($array1, $array2);

查看有多少键值对匹配，只需count($intersect);

查看第一个数组的最后两个键是否匹配，只需这样写:

$lastKeys = array_slice(array_keys($array1), -2);
if (isset($intersect[$lastKeys[0]]) && isset($intersect[$lastKeys[1])) {
    return 'match';
}
return 'no match';

查看array_slice的详细信息。

$array1 = array("a" => "greens", "reds", "blues", "red");
$array2 = array("b" => "green", "yellow", "red");
$result = array_intersect($array1, $array2);
 if(is_array($result)){
    echo 'match';
 }else{
    echo 'not match';
 }