我有下一个问题：
我有下一个AJAX：
$.ajax({
data: parametros,
url: 'attack.php',
type: 'get',
beforeSend: function() {
$("#attack").html("Wait please...");
},
success: function(response) {
//Response saying succes attack
$("#attack").html(response);
score = //returned score via AJAX;
}
});
和PHP：
//Some BD connections and querys
if ($win == true) {
//The message
echo "You won the battle!";
//The value that must be returned
$score = $score + 10;
}else {
//The message
echo "You been defeted in battle!";
//The value that must be returned
$score = $score + -10;
}
我需要从attak.php中获得一些返回值，将其放入我的var分数中。但我找不到路，我看到一些帖子说要同步做，除了异步，但我不明白…
希望任何人都能发布一个如何从我的PHP中获取返回参数的例子，谢谢！
您可以从服务器json_encode您的响应，然后从中访问多个变量。
php
$data = array();
if ($win == true) {
//The message
$data['msg'] = "You won the battle!";
//The value that must be returned
$data['score'] = $score + 10;
}else {
//The message
$data['msg'] = "You been defeted in battle!";
//The value that must be returned
$data['score'] = $score -10;
}
echo json_encode($data);
jQuery
$.ajax({
data: parametros,
url: 'attack.php',
type: 'get',
dataType: 'json', // telling the function to expect json response
beforeSend: function() {
$("#attack").html("Wait please...");
},
success: function(response) {
// accessing array variables via keys
$("#attack").html(response.msg);
score = response.score;
}
});
注意：请确保除了$data数组之外，php页面(notices/warnings/etc(没有返回/回显其他内容，否则客户端会出现JSON错误。