如何在正斜杠之后获得文本(直到下一个正斜杠或字符串结束) - How to get text after forward slashes (up until next forward slash or end of string)?

How to get text after forward slashes (up until next forward slash or end of string)?

我有一个URL清理看起来像这样:

/foo/bar

我试过了:

preg_match('#([a-zA-z0-9]+)#', $path, $matches);

但是$匹配输出为:

Array
(
    [0] => /foo
    [1] => foo
)

可以使用什么正则表达式(即与preg_match())来获得foo和bar ?

你最好使用explosion:

print_r(explode('/',ltrim('/foo/bar','/')));

但是如果你想用regex来做(对于这个非常糟糕)，只需使用preg_match_all():

preg_match_all('/([a-zA-Z0-9]+)/','/foo/bar', $matches);
echo '<pre>';
print_r($matches[0]);

更多信息请访问:http://nl3.php.net/manual/en/function.preg-match-all.php结果都是:

Array
(
    [0] => foo
    [1] => bar
)

使用PHP爆炸():

$arr = explode('/', substr($str,1) );

Array(
   [0] = 'foo';
   [1] = 'bar'
)