如何在PHP trait中使用数组引用声明抽象方法

当试图使用一个具有抽象方法声明的trait的类时，并且该抽象方法声明的参数类型为引用数组

我得到以下错误:

致命错误:MyTrait和MyClass在MyClass的组合中定义了相同的属性($foo)。然而，定义不同，被认为是不相容的。类在MyClass 中组成

如何在trait中声明抽象方法，以要求展示类只接受数组引用作为输入参数?

Trait和展示类中指向数组引用的形参的适当语法是什么?

(更新)例子:

<?php
const LOCATION_PRECISION = 7;
const LOCATION_LAT = '40.7591523';
const LOCATION_LNG = '-73.9777136';
trait Geocodes
{
    protected $recast = [];
    protected $precision = LOCATION_PRECISION;
    abstract function reCast(array &$payload);
}
class Location
{
    use Geocodes;
//FATAL: can't override here!
//protected $recast = [
//    'lat' => ['index' => 'lat', 'type' => 'double'],
//    'lng' => ['index' => 'lng', 'type' => 'double']
//];
protected $lat = LOCATION_LAT;
protected $lng = LOCATION_LNG;
public function __construct()
{
   $this->precision = LOCATION_PRECISION;
   $this->recast['lat'] = ['index' => 'lat', 'type' => 'double'];
   $this->recast['lng'] = ['index' => 'lng', 'type' => 'double'];
}
public function recast(array &$payload)
{
  foreach(array_keys($payload) as $key)
  {
      var_dump($payload);
      $api_key = $this->recast[$key]['index'];
      $api_type = $this->recast[$key]['type'];
      if(! array_key_exists($api_key, $payload))
            $payload[$api_key] = bcadd($payload[$key],0,$this->precision);
  }
}
public function getLat() { return $this->lat; }
public function getLng() { return $this->lng; }
}
$loc = new Location();
$payload = ['lat' => $loc->getLat(), 'lng' => $loc->getLng()];
$loc->recast($payload);
echo PHP_EOL.print_r($payload, 1).PHP_EOL;