PHPUnit静默失败


PHPUnit fails silenlty

当我单独运行$ phpunit时,它默默地失败了,这就是我试图知道问题是什么,没有运气:

$ phpunit
$ echo $?
=> 255

$ php -i | grep error

display_errors => STDOUT => STDOUT
display_startup_errors => On => On
error_append_string => no value => no value
error_log => /usr/local/var/log/php_error.log => /usr/local/var/log/php_error.log
error_prepend_string => no value => no value
error_reporting => 32767 => 32767
html_errors => Off => Off
ignore_repeated_errors => Off => Off
log_errors => On => On
log_errors_max_len => 1024 => 1024
track_errors => On => On
xmlrpc_error_number => 0 => 0
xmlrpc_errors => Off => Off
xdebug.force_display_errors => On => On
xdebug.force_error_reporting => 1 => 1
xdebug.show_error_trace => Off => Off
opcache.error_log => no value => no value

phpunit --version
PHPUnit 6.0-g969991b by Sebastian Bergmann and contributors.

php --version
PHP 7.0.10-1 (cli) ( NTS )
Copyright (c) 1997-2016 The PHP Group
Zend Engine v3.0.0, Copyright (c) 1998-2016 Zend Technologies
    with Zend OPcache v7.0.10-1, Copyright (c) 1999-2016, by Zend Technologies
    with Xdebug v2.4.0, Copyright (c) 2002-2016, by Derick Rethans

检查语法错误,返回一切正常:

for f in $(find tests/)
> do php -l $f
> done
...

作为临时解决方案,我按照

下面的方式运行所有测试

find . -name "*_Test.php" -type f -exec phpunit {} ';

php_error.log没有日志条目,为了确保文件上没有写入任何内容:

$ truncate -s0 /usr/local/var/log/php_error.log
$ phpunit
$ tail /usr/local/var/log/php_error.log

和我有写访问do日志文件:-rw-rw-r-- 1 adam adam 0 Sep 2 11:49 /usr/local/var/log/php_error.log

和安全:

$ php -r "error_log('am i logged?');"
$ tail /usr/local/var/log/php_error.log
[02-Sep-2016 13:16:37 Europe/Paris] am i logged?

phpunit tests/*只有根目录上的文件在运行测试, phpunit不会递归地

这是phpunt .xml

<?xml version="1.0" encoding="UTF-8"?>
<phpunit backupGlobals="false"
         backupStaticAttributes="false"
         colors="true"
         convertErrorsToExceptions="true"
         convertNoticesToExceptions="true"
         bootstrap="bootstrap.php"
         convertWarningsToExceptions="true"
         processIsolation="false"
         stopOnFailure="false">
    <testsuites>
        <testsuite name="Application Test Suite">
            <directory suffix=".php">./tests</directory>
        </testsuite>
    </testsuites>
</phpunit>

,这是bootstrap.php文件

的内容
<?php
//
// Author: Oussama Elgoumri
// Email : ktsnepyg9igfz1@gmail.com
//
// Wed Aug 31 17:13:04 WEST 2016
//

require_once __DIR__ . '/vendor/autoload.php';
require_once dirname(dirname(__FILE__)) . '/wp-load.php';
require_once ABSPATH . 'wp-admin/includes/admin.php';

use Dotenv'Dotenv;

do_action('admin_init');
(new Dotenv(__DIR__))
    ->load();

我知道没有错误,这很奇怪,echo $?在运行phpunit后返回255,因为当我运行

psysh bootstrap.php没有错误

我将感谢任何帮助,即使它是hacki,我只是想运行测试覆盖,并产生一个报告。谢谢你

作为临时解决方案,我使用以下命令运行所有测试:find . -name "*_Test.php" -type f -exec phpunit {} ';

test single file

$ phpunit tests/Upload__FN_Test.php
PHPUnit 5.5.4 by Sebastian Bergmann and contributors.
.                                                                   1 / 1 (100%)
Time: 1.27 seconds, Memory: 24.00MB
OK (1 test, 1 assertion)

测试目录中的所有文件目录应该不能包含子目录,否则它将失败,如上面所解释的255错误

$ phpunit tests/src/Uptobox/Workflow_PHP/
PHPUnit 5.5.4 by Sebastian Bergmann and contributors.
.....                                                               5 / 5 (100%)
Time: 7.03 seconds, Memory: 26.00MB
OK (5 tests, 6 assertions)

测试覆盖目录下的文件

$ phpunit tests/src/Uptobox/Workflow_PHP/ --coverage-text --whitelist src/Uptobox/Uptobox.php
PHPUnit 5.5.4 by Sebastian Bergmann and contributors.
.....                                                               5 / 5 (100%)
Time: 6.93 seconds, Memory: 28.00MB
OK (5 tests, 6 assertions)

Code Coverage Report:    
  2016-09-02 12:35:00    
 Summary:                
  Classes:  0.00% (0/1)  
  Methods: 75.00% (3/4)  
  Lines:   90.91% (10/11)
'App'Uptobox::Uptobox
  Methods:  75.00% ( 3/ 4)   Lines:  90.91% ( 10/ 11)

到目前为止,我注意到只要目标目录不包含任何子目录,phpunit就会处理该目录下的所有测试文件,否则它会静默失败。

您的目录后缀可能是错误的。

这里:你试图执行每个php文件作为测试:

<testsuites>
    <testsuite name="Application Test Suite">
        <directory suffix=".php">./tests</directory>
    </testsuite>
</testsuites>

但是这里你把它限制为"*_Test.php"

find . -name "*_Test.php" -type f -exec phpunit {} ';

试题:

<testsuites>
    <testsuite name="Application Test Suite">
        <directory suffix="Test.php">./tests</directory>
    </testsuite>
</testsuites>