我有一个HTML文档,在标签中有一些图像。我想改变每个img源(src)与不同的,定义在数组,值。
当我运行以下代码时,我得到
<>之前警告:preg_replace():第9行/var/www/test.php中未知的修饰符'/'警告:preg_replace():第9行/var/www/test.php中未知的修饰符'/'之前如何正确转义url字符串?
<?php
$body = "<img src=http://www.google.com/img1.jpg><br>"
+ "<img width=300 src=http://www.bbc.co.uk/img1.jpg>";
$changes = array();
$changes[] = array('from' => 'http://www.google.com/img1.jpg',
'to' => 'http://cnn.com/image2.jpg');
$changes[] = array('from' => 'http://www.bbc.co.uk/img1.jpg',
'to' => 'http://www.foo.bar.com/image2.jpg');
foreach ($changes as $change){
$body = preg_replace('/<(img.*src)="'.$change['from'].'".*'/?>/',
'<'1="'.$change['to'].'">', $body)
. PHP_EOL;
}
?>
试试这个:
http://php.net/manual/en/function.urlencode.php用于编码url。
然而,看起来你只是试图替换$body中字符串的一部分,所以我使用
http://php.net/manual/en/function.str-replace.php代替正则表达式
<?php
$body = "<img src=http://www.google.com/img1.jpg><br><img width=300 src=http://www.bbc.co.uk/img1.jpg>";
$changes = array();
$changes[] = array('from' => 'http://www.google.com/img1.jpg', 'to'=> 'http://cnn.com/image2.jpg');
$changes[] = array('from' => 'http://www.bbc.co.uk/img1.jpg', 'to' => 'http://www.foo.bar.com/image2.jpg');
foreach ($changes as $change){
$body = str_replace($change['from'],$change['to'],$body);
}
?>