当前构建WordPress主题和wpautop函数非常困难。说到regex，我几乎是个十足的傻瓜，我想知道是否有人能帮我。
假设我有：
<p><img src="img/something.jpg" width="1249124" height="20" alt="foo" /></p>
我该如何替换它，并且基本上只去掉<p></p>标签。请记住，还有其他内容，所以我不能完全排除所有<p>标签。
这是内容：
<p><img src="http://85.17.31.78/~tfbox/wp-content/uploads/2011/08/spotify4.jpg" alt="foo" /></p>
<p>The path of the righteous man is beset on all sides by the iniquities of the selfish and the tyranny of evil men. Blessed is he who, in the name of charity and good will, shepherds the weak through the valley of darkness, for he is truly his brother's keeper and the finder of lost children. And I will strike down upon thee with great vengeance and furious anger those who would attempt to poison and destroy My brothers. And you will know My name is the Lord when I lay My vengeance upon thee.</p>
<p>The path of the righteous man is beset on all sides by the iniquities of the selfish and the tyranny of evil men. Blessed is he who, in the name of charity and good will, shepherds the weak through the valley of darkness, for he is truly his brother's keeper and the finder of lost children. And I will strike down upon thee with great vengeance and furious anger those who would attempt to poison and destroy My brothers. And you will know My name is the Lord when I lay My vengeance upon thee.</p>
<p>The path of the righteous man is beset on all sides by the iniquities of the selfish and the tyranny of evil men. Blessed is he who, in the name of charity and good will, shepherds the weak through the valley of darkness, for he is truly his brother's keeper and the finder of lost children. And I will strike down upon thee with great vengeance and furious anger those who would attempt to poison and destroy My brothers. And you will know My name is the Lord when I lay My vengeance upon thee.</p>
这是脚本：
function ptags() {
$c = get_the_content();
echo preg_replace('#(.*?)<p>'s*(<img[^<]+?)'s*</p>(.*)#s', '$1$2$3', $c);
}
add_filter('the_content', 'ptags', 9);
$str = '<p><img src="img/something.jpg" width="1249124" height="20" alt="foo" /></p>';
$str = preg_replace('%(.*?)<p>'s*(<img[^<]+?)'s*</p>(.*)%is', '$1$2$3', $str);
编辑：这是图案说明
Match the regular expression below and capture its match into backreference number 1 «(.*?)»
Match any single character that is not a line break character «.*?»
Between zero and unlimited times, as few times as possible, expanding as needed (lazy) «*?»
Match the characters “<p>” literally «<p>»
Match a single character that is a “whitespace character” (spaces, tabs, and line breaks) «'s*»
Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
Match the regular expression below and capture its match into backreference number 2 «(<img[^<]+?)»
Match the characters “<img” literally «<img»
Match any character that is NOT a “<” «[^<]+?»
Between one and unlimited times, as few times as possible, expanding as needed (lazy) «+?»
Match a single character that is a “whitespace character” (spaces, tabs, and line breaks) «'s*»
Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
Match the characters “</p>” literally «</p>»
Match the regular expression below and capture its match into backreference number 3 «(.*)»
Match any single character that is not a line break character «.*»
Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
为什么前面的答案有这么多代码？
我可以考虑一个更短的解决方案：
$result = preg_replace('%<p>(<img .*?/>)</p>%i', '$1', $html);