我正在尝试从mysql解析文章,并用php将数据编码为json。
目前发表的文章我使用:
<?php if ($success): ?>
<?php foreach($article->get_items() as $item): ?>
<?php echo $item->get_content(); ?>
<?php endforeach; ?>
<?php endif; ?>
我正在尝试将其编码为json。
我试过这个:
<?php if ($success): ?>
<?php foreach($feed->get_items() as $item): ?>
<?php
$data = array(
'id' => "1",
'result' => array(
'title' => 'This is the title',
'publish' => 'John Doe',
'content' => $item->get_content()
)
);
echo json_encode($data);
?>
<?php endforeach; ?>
<?php endif; ?>
此外,我不确定如何使用foreach((以便解析和编码所有内容。
更新:
从$item->get_content((解析的内容具有HTML元素,如、等,因此它们应该被编码为json或字符串?
更新2:
问题是,目前我的结局是:
[
{"id":"1","result":{"title":"This is the title","publish":"John Doe","content":"content 1"}},
{"id":"1","result":{"title":"This is the title","publish":"John Doe","content":"content 1"}},
{"id":"1","result":{"title":"This is the title","publish":"John Doe","content":"content 1"}},
{"id":"1","result":{"title":"This is the title","publish":"John Doe","content":"content 1"}},
{"id":"1","result":{"title":"This is the title","publish":"John Doe","content":"content 1"}}
]
因为我没有正确使用foreach((,我想最终得到这个:
[
{"id":"1","result": {"title":"This is the title","publish":"John Doe","content":"content 1"},
{"title":"This is the title","publish":"John Doe","content":"content 1"},
{"title":"This is the title","publish":"John Doe","content":"content 1"},
{"title":"This is the title","publish":"John Doe","content":"content 1"},
{"title":"This is the title","publish":"John Doe","content":"content 1"}
]
还有内容,有时它包含html元素,这会破坏json编码,所以我想我必须将其编码为json或字符串?
创建一个保存所有数据的数组,然后将其编码为json
if ($success){
$result = array();
foreach($feed->get_items() as $item){
$data = array(
'id' => "1",
'result' => array(
'title' => 'This is the title',
'publish' => 'John Doe',
'content' => $item->get_content()
)
);
array_push($result,$data);
}
echo json_encode($result);
}
<?php
foreach($article->get_items() as $item){
$result[] = array(
'title' => 'This is the title',
'publish' => 'John Doe',
'content' => $item->get_content()
);
);
}
echo json_encode(array('id'=>'1', 'result'=>$result));
?>
事实上,我不确定我是否理解你需要什么,所以也许这不会有帮助。
输出包含HTML
代码的字符串时,您需要使用htmlspecialchars
:
echo htmlspecialchars(json_encode($data));
例如:
$data = array('id' => '<hello>');
echo htmlspecialchars(json_encode($data));
// Outputs: {"id":"<hello>"}