我正在为我的网站做一个PHP twitter feed。到目前为止，我已经弄清楚了如何输出日期，但我想做的是挑选出url并超链接它们。我还想挑出#标签，超链接到推特上搜索。我刚刚开始学习PHP，所以任何帮助都会很感激。
<?php
$count = 5;
$tweet=json_decode(file_get_contents("http://api.twitter.com/1/statuses/user_timeline/atrueresistance.json?count=".$count."" ));
for ($i=1; $i <= $count; $i++){
echo "<div class='tweet'>".$tweet[($i-1)]->text."
<div class='tweet_date'>". date("M '- j",strtotime($tweet[($i-1)]->created_at))."
</div>
</div>";
}
?>
既然没有人回应这个问题，我想是时候把我想到的代码放上去了。
享受吧!
<?php
$count = 5;
$tweet=json_decode(file_get_contents("http://api.twitter.com/1/statuses/user_timeline/atrueresistance.json?count=".$count."" ));
for ($i=1; $i <= $count; $i++){
//Assign feed to $feed
$feed = $tweet[($i-1)]->text;
//Find location of @ in feed
$feed = str_pad($feed, 3, ' ', STR_PAD_LEFT); //pad feed
$startat = stripos($feed, '@');
$numat = substr_count($feed, '@');
$numhash = substr_count($feed, '#');
$numhttp = substr_count($feed, 'http');
$feed = preg_replace("/(http:'/'/)(.*?)'/(['w'.'/'&'='?'-',':';'#'_'~'%'+]*)/", "<a href='"''0'">''0</a>", $feed);
$feed = preg_replace("(@([a-zA-Z0-9'_]+))", "<a href='"http://www.twitter.com/''1'">''0</a>", $feed);
$feed = preg_replace('/(^|'s)#('w+)/', ''1<a href="http://search.twitter.com/search?q=%23'2">#'2</a>', $feed);
echo "<div class='tweet'>".$feed. "<div class='tweet_date'>". date("M '- j",strtotime($tweet[($i-1)]->created_at))."
</div></div>";
}?>