我在Laravel 5.1中设置了一个全局作用域,它工作得很好。然而,在我的一些页面上,我使用MySQL joins
使用雄辩的建设者。这会导致一个模棱两可的错误:
Column 'cust_id' in where clause is ambiguous
我不知道如何避免这个问题。我知道我可以使用子查询代替,但有没有其他的解决方案?
这是我的作用域文件:
<?php
namespace App'Scopes;
use Illuminate'Database'Eloquent'Model;
use Illuminate'Database'Eloquent'Builder;
use Illuminate'Database'Eloquent'ScopeInterface;
use App'Customers;
use DB, Session;
class MultiTenantScope implements ScopeInterface
{
/**
* Create a new filter instance.
*
* @param UsersRoles $roles
* @return void
*/
public function __construct()
{
$this->custId = Session::get('cust_id');
}
/**
* Apply scope on the query.
*
* @param Builder $builder
* @param Model $model
* @return void
*/
public function apply(Builder $builder, Model $model)
{
if($this->custId)
{
$builder->whereCustId($this->custId);
}
else
{
$model = $builder->getModel();
$builder->whereNull($model->getKeyName());
}
}
/**
* Remove scope from the query.
*
* @param Builder $builder
* @param Model $model
* @return void
*/
public function remove(Builder $builder, Model $model)
{
$query = $builder->getQuery();
$query->wheres = collect($query->wheres)->reject(function ($where)
{
return ($where['column'] == 'cust_id');
})->values()->all();
}
}
为了消除字段的歧义,您应该添加表名作为前缀:
public function apply(Builder $builder, Model $model)
{
if($this->custId)
{
$fullColumnName = $model->getTable() . ".cust_id";
$builder->where($fullColumnName, $this->custId);
}
else
{
$model = $builder->getModel();
$builder->whereNull($model->getKeyName());
}
}