第二个Zip文件抛出无效或未初始化的Zip对象


Second Zip file throwing Invalid or unitialized Zip Object

我正试图解压缩另一个zip文件中的zip文件,以获取第二个zip文件中的xml文件。

这个文件最大的挑战是,zip文件中的文件总是不同的,因此是未知的。因此,我创建了一个函数,将存档的档案列表放入文本列表中。然后使用这个列表来解压缩每个文件,并从第二个zip文件中的xml文件中提取所需的信息。

这是目前为止我的代码。

//Set the date
$day = date("mdY");
echo $day."<br>";
//URL to download file from for updating the prescription table
//$url = "ftp://public.nlm.nih.gov/nlmdata/.dailymed/dm_spl_daily_update_".$day.".zip";
  $url = "ftp://public.nlm.nih.gov/nlmdata/.dailymed/dm_spl_daily_update_09152016.zip";
//Saving the file on the server. 
 file_put_contents("Prescription_update.zip", fopen($url, 'r'));
//unzip the downloaded file
 $zip = new ZipArchive;
 if($zip->open('Prescription_update.zip')){
      $path = getcwd() . "/update/";
      $path = str_replace("''","/",$path); 
     //echo $path;
      $zip->extractTo($path);
      $zip->close();
     print 'ok<br>';
  } else {
     print 'Failed';
}

// integer starts at 0 before counting
$i = 0; 
$dir = '/update/prescription/';
if ($handle = opendir($dir)) {
    while (($file = readdir($handle)) !== false){
        if (!in_array($file, array('.', '..')) && !is_dir($dir.$file)) 
            $i++;
    }
}
// prints out how many were in the directory need this for the loop later
   echo "There were $i files<br>";

 $dh  = opendir($dir);
 $files = array();
 while (false !== ($filename = readdir($dh))) {
     $files[] = $filename." 'r'n";
 }
  //Created a list of files in the update/prescription folder
   file_put_contents("list.txt", $files);

 /*
  *  Creating a loop here to ready the names and extract the 
  *  XML file from the zipped files that are in the update/prescription folder
  *
  */
  $ii = 2;
  $fileName = new SplFileObject('list.txt');
  $fileName->seek($ii);
  echo $fileName."<br>";   //return the first file name from list.txt
  $zip = new ZipArchive;
  $zipObj = getcwd()."/update/prescription/".$fileName;
  $zipObj = str_replace("''","/", $zipObj);
  echo $zipObj."<br>";
 if($zip->open($zipObj)){
       $path = getcwd() . "/update/prescription/tmp/";
       $path = str_replace("''","/",$path); 
       mkdir($path);
       echo $path;
       $zip->extractTo($path);
       $zip->close();
       print 'ok<br>';
    } else {
       print 'Failed';
  }

不知道为什么第二个ZipArchive::extractTo:抛出错误。我以为可能是路径问题。所以我换了第二根绳子,希望能解决问题,但没有。所以,举起我的双手,请求另一双眼睛来关注这个问题。

UPDATE ERROR LOG ENTRY

   [18-Sep-2016 02:24:24 America/Chicago] PHP   1. {main}() C:'emr-wamp'www'interface'weno'update_prescription_drug_table.php:0
   [18-Sep-2016 02:24:24 America/Chicago] PHP   2. ZipArchive->extractTo() C:'emr-wamp'www'interface'weno'update_prescription_drug_table.php:76
   [18-Sep-2016 02:24:24 America/Chicago] PHP Warning:  ZipArchive::close(): Invalid or unitialized Zip object in C:'emr-wamp'www'interface'weno'update_prescription_drug_table.php on line 77
 [18-Sep-2016 02:24:24 America/Chicago] PHP Stack trace:
 [18-Sep-2016 02:24:24 America/Chicago] PHP   1. {main}() C:'emr-wamp'www'interface'weno'update_prescription_drug_table.php:0
 [18-Sep-2016 02:24:24 America/Chicago] PHP   2. ZipArchive->close() C:'emr-wamp'www'interface'weno'update_prescription_drug_table.php:77

我本来打算投票删除这个问题,但我认为从长远来看,最好还是把它留下。

答案是

如何让PHP ZipArchive与变量

一起工作

似乎整个名称不能作为一个变量。但是,如果您将名称的一部分作为子名称,则允许这样做。

 $zipObj = getcwd()."/update/prescription/".$fileName;

必须加上

 $z->open("update/".$r.".zip"){
    //do something here
 }