我是开发界的新手，刚刚开始学习PHP。我有一个基本表单，它尝试验证用户选择或选中的复选框。我的代码如下。我的问题是，为什么当我有我的表单的顺序如下，表单不传递值。NET, PHP或RUBY和不断传递的值是没有。
——不工作的表单代码——
<form name="checkboxes" method="post" action="form_sample_checkboxes.php">
<input type="checkbox" name="ch1" value="net" <?php print $ch1status ?>>.NET
<input type="hidden" name="ch1" value="no">
<input type="checkbox" name="ch2" value="php" <?php print $ch2status ?>>PHP
<input type="hidden" name="ch2" value="no">
<input type="checkbox" name="ch3" value="ruby" <?php print $ch3status ?>>Ruby on Rails
<input type="hidden" name="ch3" value="no">
<input type="submit" name="submit" value="submit">
但是如果我的代码如下;
<form name="checkboxes" method="post" action="form_sample_checkboxes.php">
<input type="hidden" name="ch1" value="no">
<input type="checkbox" name="ch1" value="net" <?php print $ch1status ?>>.NET
<input type="hidden" name="ch2" value="no">
<input type="checkbox" name="ch2" value="php" <?php print $ch2status ?>>PHP
<input type="hidden" name="ch3" value="no">
<input type="checkbox" name="ch3" value="ruby" <?php print $ch3status ?>>Ruby on Rails
<input type="submit" name="submit" value="submit">
</form>
显示复选框。
<?php
$ch1status = "unchecked";
$ch2status = "unchecked";
$ch3status = "unchecked";
if(isset($_POST["submit"])) {
if(isset($_POST["ch1"])) {
if($_POST["ch1"] == "net") {
$ch1status = "checked";
}
}
if(isset($_POST["ch2"])) {
if($_POST["ch2"] == "php") {
$ch2status = "checked";
}
}
if(isset($_POST["ch3"])) {
if($_POST["ch3"] == "ruby") {
$ch3status = "checked";
}
}
if ($_POST["ch1"] == "no" && $_POST["ch2"] == "no" && $_POST["ch3"] == "no") {
print "There is no such choice";
}
}
?>
<html>
<head>
<title>Sample form checkbxoes</title>
</head>
<body>
<form name="checkboxes" method="post" action="form_sample_checkboxes.php">
<input type="hidden" name="ch1" value="no">
<input type="checkbox" name="ch1" value="net" <?php print $ch1status ?>>.NET
<input type="hidden" name="ch2" value="no">
<input type="checkbox" name="ch2" value="php" <?php print $ch2status ?>>PHP
<input type="hidden" name="ch3" value="no">
<input type="checkbox" name="ch3" value="ruby" <?php print $ch3status ?>>Ruby on Rails
<input type="submit" name="submit" value="submit">
</form>
<?php
if(isset($_POST["submit"])) {
if(isset($_POST["ch1"])) {
print $_POST["ch1"];
print $ch1status;
}
if(isset($_POST["ch2"])) {
print $_POST["ch2"];
print $ch2status;
}
if(isset($_POST["ch3"])) {
print $_POST["ch3"];
print $ch3status;
}
}
echo "<pre>";
print_r($_POST);
echo "</pre>";
?>
</body>
</html>
</form>
是否有其他方法来验证用户是否没有选择任何复选框，而不是使用隐藏的表单字段
这只是浏览器的问题，而且很简单:元素具有相同的名称，后面的元素覆盖了第一个元素。
另一种验证方法是，如果一个复选框未被选中，则检查它是否设置在$POST -数组中。
未定义索引:
这是因为复选框只有在被选中时才会被发送。你可以做的一件事是在使用变量之前总是用isset检查变量(例如isset($_POST['ch1']));另一种方法是将复选框命名为相同的东西，并在名称后面加上[](例如name="languages[]")，然后像这样做:
// Create a list of languages that are OK (remember, some users are malicious)
$languages = array('net','php','ruby');
// Compile a list of the answers the user picked; force it to be an
// array by either explicitly casting to an array, or using an empty array
// if none chosen
$picked = isset($_POST['languages']) ? (array)$_POST['languages'] : array();
// first, use array_intersect to remove entries present in one and not the other
// i.e. invalid entries from the client or entries not picked from the whole list
// then, "flip" the array so that the values become keys,
// because isset is faster than in_array
$valid_langs = array_flip(array_intersect($languages, $picked));
// check on languages
if (isset($valid_langs['php'])) { /* PHP picked */ }
if (isset($valid_langs['net'])) { /* NET picked */ }
if (isset($valid_langs['ruby'])) { /* Ruby picked */ }
更简单的解决方案:
<form>
<input type="checkbox" name="php" value="yes" />
<input type="checkbox" name="net" value="yes" />
<input type="checkbox" name="ruby" value="yes" />
</form>
<?php
$php = $net = $ruby = 'unchecked';
if (!isset($_POST['php'],$_POST['net'],$_POST['ruby'])) {
echo 'There is no such choice';
}
else {
if (isset($_POST['php']) && $_POST['php'] == 'yes') {
$php = 'checked';
}
if (isset($_POST['net']) && $_POST['new'] == 'yes') {
$net = 'checked';
}
if (isset($_POST['ruby']) && $_POST['ruby'] == 'yes') {
$ruby = 'checked';
}
}
// ... snip ...
有很多方法可以做到这一点。
Php都是服务器端，所以为了防止它们提交，您需要客户端验证。最简单的客户端验证是使用javascript，或者jQuery的验证插件，如果你已经在使用jQuery(如果你计划在任何时候使用AJAX，你应该是)。
是的，你可以去掉那些隐藏的输入
您不需要这些隐藏字段。把它们去掉就可以了。
编辑:检查这个修改
$ch1status = "unchecked";
$ch2status = "unchecked";
$ch3status = "unchecked";
if(isset($_POST["submit"])) {
if(@$_POST["ch1"] != "") {
$ch1status = "checked";
}
if(@$_POST["ch2"] != "") {
$ch2status = "checked";
}
if(@$_POST["ch3"] != "") {
$ch3status = "checked";
}
if (@$_POST["ch1"] . @$_POST["ch2"] . @$_POST["ch3"] == "") {
print "There is no such choice";
}
}
?>
<html>
<head>
<title>Sample form checkbxoes</title>
</head>
<body>
<form name="checkboxes" method="post" action="form_sample_checkboxes.php">
<input type="checkbox" name="ch1" value="net" <?php echo $ch1status; ?>>.NET
<input type="checkbox" name="ch2" value="php" <?php echo $ch2status; ?>>PHP
<input type="checkbox" name="ch3" value="ruby" <?php echo $ch3status; ?>>Ruby on Rails
<input type="submit" name="submit" value="submit">
</form>
<?php
if(isset($_POST["submit"])) {
if(isset($_POST["ch1"])) {
print $_POST["ch1"];
print $ch1status;
}
if(isset($_POST["ch2"])) {
print $_POST["ch2"];
print $ch2status;
}
if(isset($_POST["ch3"])) {
print $_POST["ch3"];
print $ch3status;
}
}
echo "<pre>";
print_r($_POST);
echo "</pre>";
?>
</body>
</html>