我有一个表Test:
Test:
id | name
1 | aaa
2 |
3 | ccc
4 | aaa
5 |
6 | ddd
我想要的结果是name不是NULL:
aaa
ccc
aaa
ddd
我怎样才能得到:
Doctrine_Core::getTable('Test')->findBy('name', NOTNULL??) <-doesnt working
和in model with:
$this->createQuery('u')
->where('name = ?', NOTNULL ???) <- doesnt working
->execute();
试试这个:
$this->createQuery('u')
->where('name IS NOT NULL')
->execute();
是标准的SQL语法。Doctrine不会将Null值转换为正确的sql
以原则的方式,从查询生成器和Expr类。
$qb = $entityManager->createQueryBuilder();
$result = $qb->select('t')
->from('Test','t')
->where($qb->expr()->isNotNull('t.name'))
->groupBy('t.name')
->getQuery()
->getResult();
还有distinct()函数
或者直接使用Doctrine filter:
$filters[] = new Filter('name', null, 'notEqual');
然后$list = $this->get(yourDBinstance)
->setDocIdentifier('TestBundle:Test')
->setFilters($filters)
->list();