按来自另一个表的数据排序 - ordering rows by data from another table

ordering rows by data from another table

本文关键字：数据排序另一个 | 更新日期: 2023-09-27

如果我有两个表，

第一个table1:

id   name
1    John
2    Andrew
3    Serj
4    Mike
5    Adam

and Second table2:

 user_id  count  date
  2       0      01-09-2011...
  5       9      05-09-2011...
  1       5      05-09-2011...
  3       7      04-09-2011...

如何从table1中选择用户并按table2中的count、date的值排序(DESC)

我想要的结果:

1 -- Adam ( count = 9 , date = 05.. )
2 -- John ( count = 5 , date = 05.. )
3 -- Serj ( count = 7 , date = 04.. )
4 ...
5 ...
...

如果不可能，或者很难得到我想要的结果(看看我的结果)，那么就按计数和日期排序。

select * from table1 t1 
join table2 t2 on t1.id = t2.user_id 
order by date desc, count desc

使用JOIN。

SELECT name from table1
JOIN table2 ON table1.id = table2.user_id
ORDER BY table2.count, table2.date DESC

请也试一下

select * from table1 t1 
join table2 t2 on t1.id = t2.user_id 
order by date, count desc

Using INNER JOIN

   SELECT t1.name, t2.count, t2.date
   FROM table1 AS t1 INNER JOIN table2 AS t2 
   ON t1.id = t2.user_id
   ORDER BY t2.count DESC, t2.date DESC;