如何在codigniter中传递foreach in控制器中的下拉值 - how to pass the dropdown value in foreach in controller in codigniter

how to pass the dropdown value in foreach in controller in codigniter

本文关键字：控制器 in codigniter foreach | 更新日期: 2023-09-27

你好，我有麻烦，这里总是显示错误，不知道为什么，请帮助我我想在user_id和section_id中插入相同的唯一区别，像这样

from_id = 1 , assigned_for = 8 , user_id = 2, section_id = 1, month= january
from_id = 1 , assigned_for = 8 , user_id = 3, section_id = 3, month= january
from_id = 1 , assigned_for = 8 , user_id = 4, section_id = 4, month= january
from_id = 1 , assigned_for = 8 , user_id = 5, section_id = 5, month= january

视图文件

下拉列表。下拉选择员工。只允许权限和名称

允许权限

控制器功能

 $from = $this->_user['user_id'];
            if ($this->form_validation->run() == TRUE) {
            if ($select_section_ids) {
                foreach ($select_section_ids as $id) {$data = array(
                                'from_id' => $from,
                                'assigned_for' =>$this->input->post('assigned_for') ,
                                'user_id' => $this->input->post('user_names'),
                                'section_id' => $id,
                                'month' => $this->input->post('month'),
                            );
            $this->my_model->insert($data);
}}

'from_id' -登录id'assigned_for' -来自select employee的下拉菜单'user_id' -来自允许权限的名称下拉列表'section_id' -来自复选框'month'-从下拉菜单

如何插入这个m有错误:列'user_id'不能为空

您使用了错误的用户id索引名称，team_lead是一个数组，等于section_ids，因此您可以使用section_ids的$key来获得正确的team_leads。

例子:

<?php
foreach ($select_section_ids as $key => $id) {
  $data = array(
    'from_id' => $from,
    'assigned_for' => (isset($_POST['assigned_for']) ? $_POST['assigned_for'] : 0),
    'user_id' => $_POST['team_leads'][$key], // this will use the key of section_ids, which is equal to team_leads.
    'section_id' => $id,
    'month' => $_POST['month'],
);
?>

还需要注意的是，如果team_leads不等于section_ids，那么您必须像这样添加检查:

'user_id' => isset($_POST['team_leads'][$key]) ? $_POST['team_leads'][$key] : 0,