删除从php/mysql中的组合框中选择的值


Deleting a value selected from a combobox in php/mysql

我正试图从php中的MYSQL数据库中删除某个选定的值。。

[delete.php]

<form name="delete" method="POST" action="d3l3t3d.php">
    <select name="eBox" id="nname" style="width: 290px; height:40px;">
    <?php
    mysql_connect("a","b","") or die("Wrong username or password");
    mysql_select_db("TABLE") or die( "Unable to select database");
    $query = "Select * From list";
    $result = mysql_query($query);
    while ($row = mysql_fetch_array($result)) 
    { 
    $name = $row['name']; 
    echo "<option>" . $name . "</option>"; 
    } 
    echo "</select><br/><br/>"
    ?>

[d3l3t3d.php]

<?php
   $namez = $_POST['nname'];
   $name = mysql_real_escape_string($namez);
   mysql_connect("a","b",
   "") or die("Wrong username or password");
   mysql_select_db("TABLE") or die( "Unable to select database");
mysql_query("DELETE FROM list WHERE name='$name'");
?>

我得到以下错误:

注意:C:''examplep''htdocs''folder''d3l3t3d.php中的未定义索引:nname在线2

$namez = $_POST['nname'];应为$namez = $_POST['ebox'];

您可以通过元素的名称而不是id来选择元素。

$namez = $_POST['nname'];应为$namez = $_POST['eBox'];

错误:Undefined index: nname in C:'xampp'htdocs'folder'd3l3t3d.php on line 2,意味着它正在搜索属性为name = "nname"的元素,当然,该元素并不存在。你得了name = "eBox"

只是一个小的打字错误:(