我正试图从php中的MYSQL数据库中删除某个选定的值。。
[delete.php]
<form name="delete" method="POST" action="d3l3t3d.php">
<select name="eBox" id="nname" style="width: 290px; height:40px;">
<?php
mysql_connect("a","b","") or die("Wrong username or password");
mysql_select_db("TABLE") or die( "Unable to select database");
$query = "Select * From list";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result))
{
$name = $row['name'];
echo "<option>" . $name . "</option>";
}
echo "</select><br/><br/>"
?>
[d3l3t3d.php]
<?php
$namez = $_POST['nname'];
$name = mysql_real_escape_string($namez);
mysql_connect("a","b",
"") or die("Wrong username or password");
mysql_select_db("TABLE") or die( "Unable to select database");
mysql_query("DELETE FROM list WHERE name='$name'");
?>
我得到以下错误:
注意:C:''examplep''htdocs''folder''d3l3t3d.php中的未定义索引:nname在线2
$namez = $_POST['nname'];
应为$namez = $_POST['ebox'];
您可以通过元素的名称而不是id来选择元素。
$namez = $_POST['nname'];
应为$namez = $_POST['eBox'];
错误:Undefined index: nname in C:'xampp'htdocs'folder'd3l3t3d.php on line 2
,意味着它正在搜索属性为name = "nname"
的元素,当然,该元素并不存在。你得了name = "eBox"
。
只是一个小的打字错误:(