While循环,每隔一次循环的语句


While loop, statement for every other loop?

我有一个while循环,每个循环在一个列表中显示一个<li></li>,有没有一种方法告诉php,每一个循环应该回显说:

<li style="background: #222;"></li>
在我的css中,我将另一种颜色#111设置为默认值,这样我的网站的用户可以很容易地确定他们看到的是哪一行数据?

my code as request:

function user_details($dbc, $q, $details) {
echo '<ul class="userlist">';
while ($user = $q -> fetch(PDO::FETCH_ASSOC)) {
    echo '<li><span>(' . $user['id'] . ')</span> <a href="/viewaccount?id=' . $user['id'] . '">' . $user['username'] . '</a><div>';
    if ($user['admin'] > 0) {
        echo '<img class="Tooltip" src="gameimages/admin.png" width="18" height="18" title="Is game admin." alt="" />';
    }
    echo '<img class="Tooltip" src="gameimages/' . $user['gender'] . '.png" width="18" height="18" title="' . $user['gender'] . '" alt="" />';
    $last_active = time() - $user['last_active'];
    $seconds = $last_active % 60;
        $minutes = ($last_active - $seconds) / 60;
    if ($minutes <= 4) {
    echo '<img class="Tooltip" src="gameimages/active5.png" width="18" height="18" alt="" title="';
        if ($seconds == 0) {
            echo 'Last active ' . $minutes . ' minutes ago." />';
        }
        elseif ($minutes == 0) {
            echo 'Last active ' . $seconds . ' seconds ago." />';
        }
        else {
            echo 'Last active ' . $minutes . ' minutes and ' . $seconds . ' seconds ago." />';
        }
    }
    elseif ($minutes <= 9) {
        echo '<img class="Tooltip" src="gameimages/active10.png" width="18" height="18" alt="" title="';
        if ($seconds == 0) {
            echo '<strong>Last active ' . $minutes . ' minutes ago." />';
        }
        else {
            echo 'Last active ' . $minutes . ' minutes and ' . $seconds . ' seconds ago." />';
        }
    }
    elseif ($minutes <= 14) {
        echo '<img class="Tooltip" src="gameimages/active15.png" width="18" height="18" alt="" title="';
        if ($seconds == 0) {
            echo 'Last active ' . $minutes . ' minutes ago." />';
        }
        else {
            echo 'Last active ' . $minutes . ' minutes and ' . $seconds . ' seconds ago." />';
        }
    }
    if ($user['subscriber'] > 0) {
        echo '<img class="Tooltip" src="gameimages/subscriber.png" width="18" height="18" title="Subscriber with ' . $user['subscriber'] . ' days left." alt="" />';
    }
    echo '</div>';
    echo '<a href="#"><img class="Tooltip" src="gameimages/sendmessage.png" width="18" height="18" title="Send ' . $user['username'] . ' a message." alt="" /></a>';
    $is_friend = $dbc -> prepare("SELECT id, friend_id FROM friends WHERE id = ? && friend_id = ?");
    $is_friend -> execute(array($details['id'], $user['id']));
    $friend_request = $dbc -> prepare("SELECT id, id_to FROM friend_requests WHERE id = ? || id_to = ? && id = ? || id_to = ?");
    $friend_request -> execute(array($user['id'], $details['id'], $details['id'], $user['id']));
    if ($is_friend -> rowCount() > 0) {
        echo '<img class="Tooltip" src="gameimages/isfriend.png" width="18" height="18" title="Friend request sent to ' . $user['username'] . '." alt="" />';
    }
    elseif ($friend_request -> rowCount() > 0) {
        echo '<img class="Tooltip" src="gameimages/friendrequested.png" width="18" height="18" title="There is a request pending to be friends with ' . $user['username'] . '." alt="" />';
    }
    else {
        echo '<a href="/confirm?action=addfriend&amp;id=' . $user['id'] . '"><img class="Tooltip" src="gameimages/addfriend.png" width="18" height="18" title="Add ' . $user['username'] . ' as a friend." alt="" /></a></li>';
    }
}
echo '</ul>';
 }

它是在一个函数在最小,基本上每一行应该有另一个背景:)

你想让所有偶数值显示别的东西;这将使用模运算符来完成:

$index = 0;
while($user = $q->fetch(PDO::FETCH_ASSOC))
{
   if(++$index%2 == 0) //is index +1 even?
     echo '<li style="background: #222;"></li>';
   else
     echo '<li></li>';
}

如果可能,您可以更改为for循环,因为您已经定义了$index

或者更妙

$isOdd = true;
while(...){
  echo '<li class="' . ($isodd ? 'odd' : 'even'). '"></li>
  $isOdd = ! $isOdd;
}

然后把颜色放入样式表-它有一个好处,你甚至可以改变字体等。你甚至可以给它一个全新的外观,而不需要改变代码

您可以使用布尔标志来跟踪它是奇数行还是偶数行,即

$isOdd = true;
while(...){
  if($isOdd) echo '<li style="background: #222;"></li>';
  else echo '<li></li>';
  $isOdd = ! $isOdd;
}

您可以这样做:

$colors = array('111', '222');
$i = 0;
while (...) {
    echo '<li style="background: #' . $colors[$i % count($colors)] . '"></li>';
    $i++;
}

为了整洁,您还可以将while循环转换为for循环。例如:

$colors = array('111', '222');
for ($i = 0; ...; $i++) {
    echo '<li style="background: #' . $colors[$i % count($colors)] . '"></li>';
}