Jquery AJAX get from PHP

本文关键字：PHP from get AJAX Jquery | 更新日期: 2023-09-27

我有这个php和js文件

PHP

<?php
    $user_id = '10';
    echo $user_id;
?>

$(document).ready(function() {
            $.ajax({
                url:"uid.php",
                success:function(data){
                    alert(data);
}
});
});

我得到"10"作为警报

但是对于PHP和JS来说，没有警告

PHP

<?php
class uidclass{
function uid_func($event, $arguments)
{
    $user_id = '10';
    echo $user_id;
}
}
?>

$(document).ready(function() {
            $.ajax({
                url:"uid.php",
                success:function(data){
                    alert(data);
}
});
});

Thanks in advance

您需要正确使用类和方法

<?php
class uidclass{
    function uid_func($event, $arguments) {
        $user_id = '10';
        echo $user_id;
    }
}
$bob = new uidclass;
$bob->uid_func(null,null); // since the parameters are not defined

或者像这样

<?php
class uidclass{
    function uid_func($event = null, $arguments = null) {
        $user_id = '10';
        return $user_id;
    }
}
$bob = new uidclass;
print $bob->uid_func(); // we have already set defaults in the function definition

或者甚至添加一个构造函数并在方法中打印

<?php
class uidclass{
    public function uid_func($event = null, $arguments = null) {
        $user_id = '10';
        print $user_id;
    }
    public function __construct() {
        $this->uid_func();
    }
}
$bob = new uidclass();