返回如果数组为空


echo if array empty

我一直在编写一些代码,根据教师上传的内容与同事和学生分享的数量来给他们颁发徽章。

当数组为空时,我遇到了一个问题。

我尝试了一个empty()函数,但我一定把它放在了错误的位置,因为它开始出现在上传的用户。

所以在下面的代码中,它是"if $uploads <我有困难的部分>

. .由此产生的问题是我如何得到一个消息来回声mysql_fetch_array($upload_count)是空的?

     <?php

$total_uploads = mysql_query("SELECT members.member_id, members.member_firstname,           members.member_lastname, COUNT(*)  
FROM uploads    
JOIN members
ON uploads.member_id = members.member_id
GROUP BY uploads.member_id   ");
$total_uploads_count    = @mysql_num_rows($total_uploads);
$upload_count = mysql_query("SELECT members.member_id, members.member_firstname,  members.member_lastname, COUNT(*)  
FROM uploads    
JOIN members
ON uploads.member_id = members.member_id AND members.member_id = ".     $_SESSION['member_id']  . "
GROUP BY uploads.member_id   ");
while($row_count=mysql_fetch_array($upload_count))  
{  

$uploads =  $row_count['COUNT(*)'];
 $unlock2 = 5 - $row_count['COUNT(*)'] ;
 $unlock3 = 20 - $row_count['COUNT(*)'] ;
 $unlock4 = 50 - $row_count['COUNT(*)'] ;
 $unlock5 = 100 - $row_count['COUNT(*)'] ;
 $unlock6 = 200 - $row_count['COUNT(*)'] ;           

 echo " you have <span class ='"blue_inherit'"> $uploads </span> uploads.<br/><br/>";
 if  ($uploads  < 1 )
 {
echo "Upload a resource to share in order to unlock your novice uploader badge!<br/>
 <img src='"images/badges/badge_e_share_1_locked.png'" width='"200'" height='"200'" alt='"Sharing Badge'" />";
 }
    else if  ($uploads >= 1 && ($uploads < 5 ))
 {
echo "Well done, you've unlocked your novice sharer's badge. <br/>
 <img src='"images/badges/badge_e_share_1.png'" width='"200'" height='"200'" alt='"Sharing Badge'" /><br/>

 If you upload $unlock2 more resources, you can unlock your E-sharing advanced beginner's badge. <br/>
  <img src='"images/badges/badge_e_share_2_locked.png'" width='"200'" height='"200'" alt='"Sharing Badge'" /><br/>

 ";
 }

    else if  ($uploads >= 5 && ($uploads < 20 ))
 {
echo "Well done, you've unlocked your E-sharing advanced beginner's badge. <br/>
 <img src='"images/badges/badge_e_share_2.png'" width='"200'" height='"200'" alt='"Sharing Badge'" /><br/>

 If you upload $unlock3 more resources, you can unlock your E-sharing mini-hero badge. <br/>
  <img src='"images/badges/badge_e_share_3_locked.png'" width='"200'" height='"200'" alt='"Sharing Badge'" /><br/> ";
 }

else if  ($uploads >= 20 && ($uploads < 50 ))
 {
echo "Well done, you've unlocked your E-sharing mini-hero badge. <br/>
 <img src='"images/badges/badge_e_share_3.png'" width='"200'" height='"200'" alt='"Sharing Badge'" /><br/>

 If you upload $unlock4 more resources, you can unlock your E-sharing hero badge. <br/>
  <img src='"images/badges/badge_e_share_4_locked.png'" width='"200'" height='"200'" alt='"Sharing Badge'" /><br/> ";
 }   
else if  ($uploads >= 50 && ($uploads < 100 ))
 {
echo "Well done, you've unlocked your E-sharing hero badge. <br/>
 <img src='"images/badges/badge_e_share_4.png'" width='"200'" height='"200'" alt='"Sharing Badge'" /><br/>

 If you upload $unlock5 more resources, you can unlock your E-sharing super-hero badge. <br/>
  <img src='"images/badges/badge_e_share_5_locked.png'" width='"200'" height='"200'" alt='"Sharing Badge'" /><br/> ";
 }       
else if  ($uploads >= 100 && ($uploads < 200 ))
 {
echo "Well done, you've unlocked your E-sharing super-hero badge. <br/>
 <img src='"images/badges/badge_e_share_5.png'" width='"200'" height='"200'" alt='"Sharing Badge'" /><br/>

 If you upload $unlock6 more resources, you can unlock your E-sharing Guru badge. <br/>
  <img src='"images/badges/badge_e_share_6_locked.png'" width='"200'" height='"200'" alt='"Sharing Badge'" /><br/> ";
 }           

 else 
 {
    echo "You've now a Guru!! <br/>
      <img src='"images/badges/badge_e_share_6.png'" width='"200'" height='"200'" alt='"Sharing Badge'" /><br/> ";

 }

     }  

 ?>

不妨将变量名改为

$please_inject_me, $please_inject_me1等等…

第一课是请使用PDO

现在谈谈你的问题(根据我对你问题的理解):

// Do your first query prepare it and then execute it, and then do a fetch and count the number of rows returned by your $query sql query
        $sql = "SELECT members.member_id, members.member_firstname, members.member_lastname, COUNT(*) FROM uploads JOIN members ON uploads.member_id = members.member_id GROUP BY uploads.member_id ";
        $query = $pdo->prepare($sql);
        $query->execute();
        $total_uploads_count = $query->fetch(PDO::FETCH_NUM);
// I guess this query you have going is counting how far the member / teacher is away from the unlock goals here we set the variable that has the num row count
        $sql2 = "SELECT members.member_id, members.member_firstname,  members.member_lastname, COUNT(*) as 'total' FROM uploads JOIN members ON uploads.member_id = members.member_id AND members.member_id = :username GROUP BY uploads.member_id";
        $query2 -> $pdo->prepare($sql2);
        $query2->bindParam(':username', $_SESSION['member_id']); // Do not forget to bind your parameters either in a array or hard code it out like I just did
        $query2->execute();
        $row = $query2->fetch();
        $upload_count = $row['total']; // Alias of COUNT(*);
Now that you PDO queries are set up now you have to create the PDO instance like so : 
You could make a file called connec.php

,内容如下:

    //We connect to the database
    $host="xxxxxx"; // Host name
    $username="xxxxxxxxx"; // Mysql username
    $password="xxxxxxx"; // Mysql password
    $db_name="xxxxxxx"; // Database name
    // Connect to server via PHP Data Object
    $pdo = new PDO("mysql:host=xxxxx;dbname=xxxxxxxx", $username, $password);
    $pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    $pdo->setAttribute(PDO::ATTR_EMULATE_PREPARES, false);
    ?>

一旦你这样做了,那么在任何有数据库交互(查询)的页面的顶部,你就可以做:

要求 ('..................(如果你的路径是)/connect.php');

现在,你有一个方法来计算所有行在你的查询与一个单一的变量($upload_count)执行以下操作:

// get the differences in the counts
    $unlock2 = 5 - $upload_count;
    $unlock3 = 20 - $upload_count;
    $unlock4 = 50 - $upload_count;
    $unlock5 = 100 - $upload_count;
    $unlock6 = 200 - $upload_count;

现在你说的问题是如果返回的结果是空的,或者如果结果是0/没有结果,如何在数据库的东西方面进行回声。

然后输入

 if($upload_count == 0) { // This is empty 
       .................... 
     } else { // This is not empty have fun :D
       ........... 
     }
我想我已经回答了你的问题…

我相信如果mysql计数返回空而不是0

试试这个

 if (empty($uploads) === true) {
echo "Upload a resource to share in order to unlock your novice uploader badge!<br/>
     <img src='"images/badges/badge_e_share_1_locked.png'" width='"200'" height='"200'" alt='"Sharing Badge'" />";
}