我正在尝试获取一个数据库调用，以显示一条语句，如果没有返回结果，则表示找不到结果。
我该如何对我的代码进行此操作：-
$getFixtures = mysql_query("SELECT ht.name AS hometeam_name, homescore, awayscore, at.name AS awayteam_name, time, date, week, comp.competition AS comp_name, se.name AS season_name
FROM fixture
JOIN team ht
ON ht.id = fixture.hometeam
JOIN team at
ON at.id = fixture.awayteam
JOIN competition comp
ON comp.id = fixture.competition
JOIN season se
ON se.id = fixture.season
WHERE se.name = '$season' AND comp.competition = '$competitiontitle' AND date >= '$today' AND at.name = '$teamName' OR ht.name = '$teamName' AND se.name = '$season' AND comp.competition = '$competitiontitle' AND date >= '$today'
ORDER BY date ASC
");
while ($fixtureData = mysql_fetch_array($getFixtures))
{
$hfixteamlink = strtolower(str_replace(" ","-",$fixtureData['hometeam_name']));
$afixteamlink = strtolower(str_replace(" ","-",$fixtureData['awayteam_name']));
$date = date("d/m/Y", strtotime($fixtureData['date']));
?>
提前感谢
Richard
这需要一个IF语句。
$rows = mysql_fetch_array($getFixtures);
if(count($rows))
{
while ($fixtureData = $rows)
...
}
else
{
echo 'No results found';
}
if ( ! mysql_num_rows($getFixtures)) {
echo 'No results found.';
} else {
...
}