我有这个包含机场代码和城市名称的数组(大约3500行)。
code,city
"Abilene, TX ",ABI
"Adak Island, AK ",ADK
"Akiachak, AK ",KKI
"Akiak, AK ",AKI
"Akron/Canton, OH ",CAK
"Akuton, AK ",KQA
"Alakanuk, AK ",AUK
"Alamogordo, NM ",ALM
我需要将该文件转换为php数组。这是我到目前为止的代码:
if(($handle = fopen('test.csv', 'r')) !== FALSE) {
while (($data = fgetcsv($handle, 1000, ',', '"')) !== FALSE) {
echo '<pre>';
print_r($data);
echo '</pre>';
}
fclose($handle);
}
虽然我正在为fgetcsv函数设置分隔符和包围符,但我得到的结果是:
Array
(
[0] => code
[1] => city
"Abilene
[2] => TX "
[3] => ABI
"Adak Island
[4] => AK "
[5] => ADK
"Akiachak
[6] => AK "
[7] => KKI
"Akiak
[8] => AK "
[9] => AKI
"Akron/Canton
[10] => OH "
[11] => CAK
"Akuton
[12] => AK "
[13] => KQA
"Alakanuk
[14] => AK "
[15] => AUK
"Alamogordo
[16] => NM "
[17] => ALM
)
如果是换行符,您可以尝试使用暴力方法:
$file = file_get_contents("test.csv");
$data = array_map("str_getcsv", preg_split('/'r*'n+|'r+/', $file));
print_r($data);
str_getcsv
在PHP 5.3中可用,或者在手册中通过upgradephp或PHP_Compat作为解决方案。
试试这个:-
ini_set('auto_detect_line_endings', TRUE);/// (PHP's detection of line endings) write at the top.
$csvrows = array_map('str_getcsv', file($filepath));
$csvheader = array_shift($csvrows);
$csv = array();
foreach ($csvrows as $row) {
$csv[] = array_combine($csvheader, $row);
}
try-
$csv = array();
if (($file = fopen('test.csv', 'r')) === false) {
throw new Exception('There was an error loading the CSV file.');
} else {
while (($line = fgetcsv($file, 1000)) !== false) {
$csv[] = $line;
}
fclose($handle);
}
要解决这个问题,您可以尝试在使用fgetcsv
解析之前修剪每行的空白。
if (($handle = fopen('test.csv', 'r')) !== FALSE) {
while (($line = fgets($handle)) !== FALSE) {
$line = trim($line); // Trim whitespace from the line
$data = str_getcsv($line, ',', '"'); // Parse CSV data
echo '<pre>';
print_r($data);
echo '</pre>';
}
fclose($handle);
}
在更新后的代码中,我们使用fgets
读取文件的每行,然后修剪以删除任何开头或结尾的空白。最后,使用str_getcsv
对CSV
数据进行解析。