我有一个带有复选框和提交按钮的HTML代码，如下图
<form action="checkboxes.php" method="post">
<input type="checkbox" name="checkbox1" value="Yes">4K</input>
<input type="submit" name="formSubmit" value="Submit" ></input>
</form>
在我的PHP中，我有一个文件"config.php"它的功能是连接到我的数据库:
<?php
/* Database connection */
$sDbHost = 'localhost';
$sDbName = 'testowanie';
$sDbUser = 'root';
$sDbPwd = '';
$dbcon = mysqli_connect ($sDbHost, $sDbUser, $sDbPwd, $sDbName);
?>
第二个PHP文件:
<?php
include('config.php');
$sqlget = "SELECT * FROM monitory";
$sqldata = mysqli_query($dbcon, $sqlget)or die("Can't connect to the database");
if(isset($_POST['checkbox1']) &&
$_POST['checkbox1'] == 'Yes')
{
while($row = mysqli_fetch_array($sqldata, MYSQLI_ASSOC)) {
echo '.';
echo $row['cena'];
}
}
?>
这三个相互连接的文件都这样做，如果复选框被选中，则执行此SQL语句:SELECT cena FROM monitory;，但我想执行此语句"SELECT * FROM monitory WHERE cena=1000;我试着用了大概2个小时来做这个但是我真的不知道怎么做
所以您希望根据输入条件选择两种不同查询中的一种。然后这样做:-)
<?php
include('config.php');
if (isset($_POST['checkbox1']))
$sqlget = "SELECT * FROM monitory WHERE cena = 1000";
else
$sqlget = "SELECT * FROM monitory";
$sqldata = mysqli_query($dbcon, $sqlget)or die("Can't connect to the database");
while($row = mysqli_fetch_array($sqldata, MYSQLI_ASSOC)) {
echo '.';
echo $row['cena'];
}