我有一个脚本来导出MySQL数据库的内容,该数据库除了在具有前导零的列上工作良好之外。由于某些原因,它们被丢弃了。
是否有一种方法可以修改代码以保留那些前导零?
多谢!
$sql = "Select * from $DB_TBLName";
$Connect = @mysql_connect($DB_Server, $DB_Username, $DB_Password) or die("Couldn't connect to MySQL:<br>" . mysql_error() . "<br>" . mysql_errno());
//select database
$Db = @mysql_select_db($DB_DBName, $Connect) or die("Couldn't select database:<br>" . mysql_error(). "<br>" . mysql_errno());
//execute query
$result = @mysql_query($sql,$Connect) or die("Couldn't execute query:<br>" . mysql_error(). "<br>" . mysql_errno());
$file_ending = "xls";
//header info for browser
header("Content-Type: application/xls");
header("Content-Disposition: attachment; filename=$filename.xls");
header("Pragma: no-cache");
header("Expires: 0");
/*******Start of Formatting for Excel*******/
//define separator (defines columns in excel & tabs in word)
$sep = "'t"; //tabbed character
//start of printing column names as names of MySQL fields
for ($i = 0; $i < mysql_num_fields($result); $i++) {
echo mysql_field_name($result,$i) . "'t";
}
print("'n");
//end of printing column names
//start while loop to get data
while($row = mysql_fetch_row($result))
{
$schema_insert = "";
for($j=0; $j<mysql_num_fields($result);$j++)
{
if(!isset($row[$j]))
$schema_insert .= "NULL".$sep;
elseif ($row[$j] != "")
$schema_insert .= "$row[$j]".$sep;
else
$schema_insert .= "".$sep;
}
$schema_insert = str_replace($sep."$", "", $schema_insert);
$schema_insert = preg_replace("/'r'n|'n'r|'n|'r/", " ", $schema_insert);
$schema_insert .= "'t";
print(trim($schema_insert));
print "'n";
}
为了保留前导零,Excel必须将数据视为文本(或某些自定义数字格式,如"00000000")。
我从superuser.com上找到了一个可能的解决方案。基本上,以下格式的数据将被视为文本,因为该值将被双引号封装:"="00123""
我认为你的代码将改为:
[snip]
elseif ($row[$j] != "")
$schema_insert .= '"=""$row[$j]"""'.$sep;
[snip]
或任何将生成示例中所示的必要引号的内容。