CakePHP -查找模型中没有hasMany关系的hasMany关联


CakePHP - Find hasMany association without hasMany relation in Model?

我想再问你一个关于CakePHP的问题:我有2个模型用户和评论与关系1-n(一个用户有许多评论)。我想使用find()列出信息用户和它的注释格式数据返回:

Array
(
    [User] => Array
        (
            [id] => 121
            [name] => Gwoo the Kungwoo
            [created] => 2007-05-01 10:31:01
        )
    [Comment] => Array
        (
            [0] => Array
                (
                    [id] => 123
                    [user_id] => 121
                    [title] => On Gwoo the Kungwoo
                    [body] => The Kungwooness is not so Gwooish
                    [created] => 2006-05-01 10:31:01
                )
            [1] => Array
                (
                    [id] => 124
                    [user_id] => 121
                    [title] => More on Gwoo
                    [body] => But what of the 'Nut?
                    [created] => 2006-05-01 10:41:01
                )
        )
)

但我不想配置关系hasMany在模型用户为例链接:http://book.cakephp.org/2.0/en/models/associations-linking-models-together.html。我试过这个代码:

 $data = $this->User->find('all', array(
                'joins' => array(
                    array(
                        'table' => 'comment',
                        'alias' => 'Comment',
                        'type' => 'LEFT',
                        'conditions' => array(
                            'User.id = Comment.user_id'
                        )
                    ),
                    'conditions' => array(
                       'User.id' => $userId
                    ),
                     'fields' => array('User.*', 'Comment.*')
            ));

Cake返回一个包含用户重复记录的数组(例如:如果用户有2条评论,它返回用户重复的2条记录)

谁能给我另一个解决方案吗?(但除了解决方案配置有许多关系模型),谢谢。

或者你可以在你的控制器中使用bindModel

        $this->User->bindModel(
               array(
                 'hasMany'=>array(
                     'Comment' =>array(
                      'className' => 'Comment',
                      'foreignKey' => 'user_id',
                      'conditions' => array('Comment.status' => 'Active'),
                  )         
               )
            )
        ); 
        $data = $this->User->find('all',array('conditions'=>array('User.email'=>$userEmail)));

查看更多信息

看看这个答案的一些信息,通过这个链接查看绑定和解绑定模型的详细信息