ajax脚本的输出如下:
{"DATA":[{"COUNTRYCODE":"1","DESCRIPTION":"USA","COUNTRYID":"211"}, {"COUNTRYCODE":"1","DESCRIPTION":"Canada","COUNTRYID":"37"},{"COUNTRYCODE":"1","DESCRIPTION":"Dominican Republic","COUNTRYID":"224"},
我试图填充一个选择菜单与信息从这个JSON数据:
<script type="text/javascript" charset="UTF-8">
$.getJSON(
'getcountries.php',
function(data) {
var items = [];
$('#country').append(data);
$.each(data['DATA'], function(key, val) {
$.each(val, function(key, value) {
console.log(value);
});
});
}
);
问题是$('#country').append(data)(或append(data['DATA'])总是返回错误"值不实现接口Node."
谁能指出我如何能得到特定的JSON数据，我有进入选择脚本?
.append()只接受HTML字符串、DOM元素或jQuery对象
见:http://api.jquery.com/append/
我认为这是你真正想要的结果。
var data = {"DATA":[{"COUNTRYCODE":"1","DESCRIPTION":"USA","COUNTRYID":"211"},{"COUNTRYCODE":"1","DESCRIPTION":"Canada","COUNTRYID":"37"},{"COUNTRYCODE":"1","DESCRIPTION":"Dominican Republic","COUNTRYID":"224"}]};
var $select = $('#country').empty();
$select.append(
data.DATA.map(function (el, i) {
return $('<option>')
.val(el.COUNTRYID)
.text(el.DESCRIPTION)
.data('DATA', el); // in case you also want to access its COUNTRYCODE
})
);
jsFiddle: http://jsfiddle.net/terryyounghk/ZshG4/
DEMO: http://jsfiddle.net/q5Q3d/
var a = {
"DATA":[
{"COUNTRYCODE":"1","DESCRIPTION":"USA","COUNTRYID":"211"},
{"COUNTRYCODE":"1","DESCRIPTION":"Canada","COUNTRYID":"37"},
{"COUNTRYCODE":"1","DESCRIPTION":"Dominican Republic","COUNTRYID":"224"}
]
}
$.each(a.DATA, function(idx, val){
var option = "<option value='" + val.COUNTRYID + "'>" + val.DESCRIPTION + "</option>";
$('select').append(option);
});