当我试图运行此代码时，任何结果都没有显示。请帮助我
。一些代码在这里...
$result = mysql_query("select * from dataform where date between '" . $d1 . "' and '" . $d2 . "'");
if (!$result) {
echo 'No result';
}
else{
echo $d1;
echo $d2;
echo "<table class='"hovertable'">";
echo "
<tr onmouseover='"this.style.backgroundColor='#ffff66';'" onmouseout='"this.style.backgroundColor='#d4e3e5';'">";
echo "<th>File No</th>";
echo "<th>Manufactor</th>";
echo "<th>Address</th>";
echo "<th>Supplier</th>";
echo "<th>Place Site</th>";
echo "<th>Tender Ref</th>";
echo "<th>Award No</th>";
echo "</tr>";
while ($row = mysql_fetch_array($result)) {
echo "<tr onmouseover='"this.style.backgroundColor='#ffff66';'" onmouseout='"this.style.backgroundColor='#d4e3e5';'">";
echo "<th>" . $row["fileno"] . "</th>";
echo "<th>" . $row["manufacture"] . "</th>";
echo "<th>" . $row["address"] . "</th>";
echo "<th>" . $row["sup"] . "</th>";
echo "<th>" . $row["placesite"] . "</th>";
echo "<th>" . $row["tenderref"] . "</th>";
echo "<th>" . $row["awardno"] . "</th>";
echo "</tr>";
}
尝试使用反引号转义列DATE，因为它是MySQL数据类型。另一个建议是避免使用查询的字符串串联，因为它容易进行 mysql 注入。使用 PHP PDO 或 MYSQLi。
使用 PDO 的示例：
<?php
$stmt = $dbh->prepare("SELECT * FROM dataform WHERE `date` BETWEEN ? AND ?");
$stmt->bindParam(1, $d1);
$stmt->bindParam(2, $d2);
$stmt->execute();
$result = $stmt->fetchAll(PDO::FETCH_ASSOC); //Fetch all results in form of associative array.
?>
请记住始终对您的输入进行消毒。
更新 1
您没有在WHILE循环中检查状况。你现在的做法是你被分配了一个错误的值。尝试使用==
而不是
while ($row = mysql_fetch_array($result))
{
}
将其更改为此
while ($row == mysql_fetch_array($result))
{
}