我可能太累了，错过了一些非常简单的东西，但我想不出来。
尝试执行以下查询:
INSERT INTO chars (charName,charClass,charLevel,charLife,charES,charInt,charStr,charDex)
VALUES (mlkauschwitz,ranger,81,4500,50,50,300,250)
ON DUPLICATE KEY UPDATE charClass=ranger,charLevel=81,charLife=4500,charES=50,charInt=50,charStr=300,charDex=250;
导致这个错误:
"SQLSTATE[42S22]: Column not found: 1054 Unknown column 'mlkauschwitz' in 'field list'"
为什么它认为值是一个字段?
使用以下PHP:
include "db.php";
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$char = array(
'charClass'=>'ranger',
'charDex'=>'250',
'charES'=>'50',
'charInt'=>'50',
'charLevel'=>'81',
'charLife'=>'4500',
'charName'=>'mlkauschwitz',
'charStr'=>'300',
);
$sql = 'INSERT INTO chars (charName,charClass,charLevel,charLife,charES,charInt,charStr,charDex) VALUES ('.$char["charName"].','.$char["charClass"].','.$char["charLevel"].','.$char["charLife"].','.$char["charES"].','.$char["charInt"].','.$char["charStr"].','.$char["charDex"].') ON DUPLICATE KEY UPDATE charClass='.$char["charClass"].',charLevel='.$char["charLevel"].',charLife='.$char["charLife"].',charES='.$char["charES"].',charInt='.$char["charInt"].',charStr='.$char["charStr"].',charDex='.$char["charDex"].';';
$stmt = $conn->prepare($sql);
$stmt->setFetchMode(PDO::FETCH_ASSOC);
if ($stmt) {
try {
$stmt->execute();
}
catch (PDOException $e) {
var_dump($e);
}
}
charName字段是唯一的/主的
结果SQL中的值需要加引号。使用pdo，您应该这样做:
$sql = 'INSERT INTO chars (charName,charClass,charLevel,charLife,charES,charInt,charStr,charDex) VALUES (?, ?, ?, ?, ?, ?, ?, ?) ON DUPLICATE KEY UPDATE charClass='.$char["charClass"].',charLevel='.$char["charLevel"].',charLife='.$char["charLife"].',charES='.$char["charES"].',charInt='.$char["charInt"].',charStr='.$char["charStr"].',charDex='.$char["charDex"].';';
$stmt = $conn->prepare($sql);
$stmt->setFetchMode(PDO::FETCH_ASSOC);
if ($stmt) {
try {
$stmt->execute(array($char["charName"],$char["charClass"],$char["charLevel"],$char["charLife"],$char["charES"],$char["charInt"],$char["charStr"],$char["charDex"]));
}
catch (PDOException $e) {
var_dump($e);
}
}
不确定确切的语法，但您可以在手册中查找。这可以确保PDO正确引用所有值，并避免mysql注入问题。
如果mlkauschwitz不是列而是值，则需要引用
看到mysqli_escape_string ()
将查询更改为INSERT INTO chars (charName,charClass,charLevel,charLife,charES,charInt,charStr,charDex)
VALUES ('mlkauschwitz','ranger','81','4500','50','50','300','250')
ON DUPLICATE KEY UPDATE charClass='ranger',charLevel='81',charLife='4500',charES='50',charInt='50',charStr='300',charDex='250';