我在这里找到了这个解决方案
但我不能让它工作，但它可能是一些基本的，谁能建议吗?
这是PHP在我的服务器上的样子:
$ cat table.php
<?php
echo "<html><body><table>'n'n";
= fopen("temp.csv", "r");
while (( = fgetcsv()) !== false) {
echo "<tr>";
foreach ( as ) {
echo "<td>" . htmlspecialchars() . "</td>";
}
echo "</tr>'n";
}
fclose();
echo "'n</table></body></html>";
CSV文件是这样的:
$ cat temp.csv
DeviceName,counter1,counter2,counter3,counter4
DeviceName1,85%,87%,75%,63%
DeviceName2,85%,85%,74%,70%
DeviceName3,80%,81%,70%,66%
DeviceName4,78%,82%,70%,74%
DeviceName5,77%,75%,68%,58%
DeviceName6,77%,72%,66%,58%
然后进入浏览器的地址
webaddressgoeshere/php/table.php
我在控制台上得到以下内容:
GET webaddressgoeshere/php/table.php 500 (Internal Server Error)
Navigated to webaddressgoeshere/php/table.php
我的答案下面，我错过了一个变量，当我复制和粘贴。哎呀! !
$ cat table.php
<?php
echo "<html><body><table>'n'n";
$f = fopen("temp.csv", "r");
while (($line = fgetcsv($f)) !== false) {
echo "<tr>";
foreach ($line as $cell) {
echo "<td>" . htmlspecialchars($cell) . "</td>";
}
echo "</tr>'n";
}
fclose($f);
<?php
if($csv_fp = fopen('csv_file.csv','r'))
{
echo '<table>';
while ($data = fGetCsv ($csv_fp, 8096, ","))
{
// you can view the array $data holds by print_r($data); exit();
echo '<tr>';
foreach($data as $d)
{
echo '<td>'.$d.'</td>';
}
echo '</tr>';
}
echo '</table>';
}
else
{
echo 'Failed to open file';
}
看起来你的代码有一些语法问题。代码是不完整的。下面是代码:
<?php
echo "<html><body><table>'n'n";
$xfile = fopen("temp.csv", "r"); // variable was missing
while (( $line = fgetcsv($xfile)) !== false) { // here too
echo "<tr>";
foreach ( $line as $ value) { // and here
echo "<td>" . htmlspecialchars($value) . "</td>"; // and here
}
echo "</tr>'n";
}
fclose($xfile); // and here
echo "'n</table></body></html>";
?>