我正在发送两个参数From=2015-08-01和To=2015-08-31工作正常。然后如何同时传递参数(From2=2015-04-01 and To2 =2015-08-31)并获得两个输出。请不要编写任何其他函数。请告诉我。
$res1=$con->selectnonschoolround1($From,$To);
while($row=pg_fetch_array($res1))
{
$r1=$row['non_slsc_qty'];
$r2=$row['non_slst_qty'];
$r3=$row['non_slot_qty'];
$r4=$row['non_slsc_ben'];
$r5=$row['non_slst_ben'];
$r6=$row['non_slot_ben'];
$Total_qty_non_r1=$row['total_qty'];
$Total_ben_non_r1=$row['total_ben'];
}
这是类。php
class DB_con
{
function __construct()
{
$db = pg_connect("host=localhost port=5432
dbname=mydb user=postgres password=123");
}
public function selectnonschoolround1($From,$To)
{
$res1=pg_query("SELECT
SUM(non_slsc_qty) as non_slsc_qty,
SUM(non_slst_qty) as non_slst_qty,
SUM(non_slot_qty) as non_slot_qty,
SUM(non_slsc_ben) as non_slsc_ben,
SUM(non_slst_ben) as non_slst_ben,
SUM(non_slot_ben) as non_slot_ben,
SUM(non_slsc_qty+non_slst_qty+non_slot_qty) AS total_qty,
SUM(non_slsc_ben+non_slst_ben+non_slot_ben) AS total_ben
FROM table where date BETWEEN '$From' AND '$To'");
return $res1;
}
}
将函数参数作为数组传递，然后您需要使用PHP函数is_array()检查参数是否为数组。如果它是一个数组，那么循环遍历该数组并使用"from"answers"to"索引执行查询，但是在这种情况下，您需要从执行的查询返回一个数组。如果它不是一个数组，则保持代码在else部分中的样子。在这种情况下，您可以对多个值或单个值使用相同的函数。只要记住，参数应该是正确的。希望这对你有帮助:)
尝试这段代码，并根据您的需要进行更改:)。
class DB_con
{
function __construct()
{
//code
}
public function selectNonSchoolRound1($arr, $from = '', $to = '')
{
if (is_array($arr)) {
$returnArr = array();
foreach ($arr as $ars) {
$res1 = pg_query("your query using ".$ars['from'].$ars['to']);
array_push($returnArr, $res1);
}
return $returnArr;
} else {
$res1 = pg_query("your query using ".$from.$to.'variabls');
return $res1;
}
}
}
try {
$arr = array('0' =>
array('from' => '2015-08-01', 'to' => '2015-08-31'),
'1' => array('from' => '2015-08-01', 'to' => '2015-08-31')
);
$obj = new DB_con();
$result = $obj->selectNonSchoolRound1($arr);
// loop here with the $result variable
} catch (Exception $ex) {
echo $ex->getMessage();
}