我有日期$current, $start
和$end格式为m-d-Y。我想要一个条件其中,如果当前日期在开始和结束日期之间,它将显示"当前",但我就是不明白为什么在世界上它不会打印我想要的东西。哈哈
示例声明将是
$current = '07-03-2014';
$start = '06-01-2013';
$end = '08-02-2015';
if(($current > $start) && ($current < $end)) {
echo "current";
}
else {
"not current";
}
为什么我有"不电流"作为输出?我做错了什么?我很确定你也有这个问题。: D
可以直接与正确格式Y-m-d
比较或使用strtotime()
$current = date('Y-m-d', strtotime('07-03-2014'));
$start = date('Y-m-d', strtotime('06-01-2013'));
$end = date('Y-m-d', strtotime('08-02-2015'));
if(($current > $start) && ($current < $end)) {
echo "current";
}
else {
"not current";
}
您可以尝试使用strtotime
$current = '07-03-2014';
$start = '06-01-2013';
$end = '08-02-2015';
if((strtotime($current) > strtotime($start)) && (strtotime($current) < strtotime($end))) {
echo "current";
}
else {
echo "not current";
}
METHOD: 2
$current = '07-03-2014';
$start = '06-01-2013';
$end = '08-02-2015';
$current_time = strtotime($current);
$start_time = strtotime($start);
$end_time = strtotime($end);
if(($current_time > $start_time) && ($current_time < $end_time)) {
echo "current";
}
else {
echo "not current";
}
使用strtotime:
$current = '07-03-2014';
$start = '06-01-2013';
$end = '08-02-2015';
if((strtotime($current) > strtotime($start)) && (strtotime($current) < strtotime($end))) {
echo "current";
}
else {
"not current";
}