我有一个示例代码:
<?php
header('Content-Type: text/html; charset=utf-8');
$doc = new DOMDocument();
$doc->load('http://www.haivl.com/rss');
$items = $doc->getElementsByTagName('item');
foreach ($items as $key => $item) {
$titles = $item->getElementsByTagName( "title" );
$title = $titles->item(0)->nodeValue;
echo $title;
}
?>
我不能从这个url获得标题,为什么错误,可以帮助我修复这个错误!
问题出在这两行
$title = $titles->item(0)->nodeValue;
echo $titles;
您将标题值分配给$title
,但回显$titles
。$titles
是DOMNodeList
,不能隐式转换为字符串。你想做
$title = $titles->item(0)->nodeValue;
echo $title;