我正在尝试编写一个函数来插入,更新和删除数据。我可以插入数据,但不能更新数据。问题是我不能传递id
值到我的updateform。
控制器:
function update($id = 0){
$this->load->helper('form');
$this->load->helper('html');
$this->load->model('employees_model');
if($this->input->post('upsubmit')){
echo '<pre>';print_r($id);echo '</pre>';
exit();
if($this->input->post('eid')){
$this->employees_model->entry_update();
}
}
$data = $this->employees_model->general();
if((int)$id > 0){
$query =this->employees_model->get($id);
$data['txt_id']['value'] = $query['eid'];
$data['txt_name']['value'] = $query['ename'];
$data['txt_salary']['value'] = $query['esalary'];
$data['txt_emailid']['value'] = $query['eemailid'];
}
$this->load->view('employees_update',$data);
}
模型:
function general(){
$data['base'] = $this->config->item('base_url');
$data['css'] = $this->config->item('css');
$data['id']['value'] = 'eid';
$data['name'] = 'txt_name';
$data['salary'] = 'txt_salary';
$data['emailId'] = 'txt_email';
return $data;
}
function entry_update($id){
$this->load->database();
echo '<pre>';print_r($id);echo '</pre>';
exit();
$data = array(
'ename'=>$this->input->post('txt_name'),
'esalary'=>$this->input->post('txt_salary'),
'eemailid'=>$this->input->post('txt_email'),
);
echo '<pre>';print_r($data);echo '</pre>';
exit();
$this->db->where('eid',$this->input->post($data));
$this->db->update('employee',$data);
//echo '<pre>';print_r($data);echo '</pre>';
echo "Updated successfully";
}
function get($id)
{
$this->load->database();
$query = $this->db->get_where('employee',array('eid'=>$id));
return $query->row_array();
}
请建议如何通过选择id值来更新视图部分的表单页面。
这是我的工作示例代码。希望能有所帮助。
控制器 //I am using update from to preload data
function update_form($id)
{
$query=$this->product_model->get($id);
$data['id']=$query['id'];
$data['name']=$query['name'];
$data['price']=$query['price'];
$this->load->view('products/update_product',$data);
}
function update()
{
$this->product_model->save();
redirect('products/index');
}
模型 function get($id=0)
{
if($id==0)
{
$query=$this->db->get('product');
return $query->result_array();
}
else
{
$this->db->where('id',$id);
$query=$this->db->get('product');
return $query->row_array();
}
}
// if **id** is greater than zero mean update, no **id** mean insert
function save()
{
$id=$this->input->post('id');
$name=$this->input->post('name');
$price=$this->input->post('price');
$data=array
(
'name'=>$name,
'price'=>$price
);
if($id>0)
{
$this->db->where('id',$id);
$this->db->update('product',$data);
}
else
{
$this->db->insert('product',$data);
}
}
}
视图(视图/产品/update_product.php)
<?php echo form_open('products/save');?> //form_open('controller_name/function_name');
<?php echo form_hidden('id',$id);?>
<?php echo form_input('name',$name,'placeholder="enter doctor name"');?><br>
<?php echo form_input('price',$pricce,'placeholder="enter doctor phone number"');?><br>
<?php echo form_submit('','Update');?>
<?php echo form_close();?>
id在更新中扮演重要的角色,你不应该把它作为隐藏字段包含在视图中
首先创建带有参数$id的函数。但是当你调用不带参数的函数时。修改这一行
in Controller change this line
$this->employees_model->entry_update();
$this->employees_model->entry_update($this->input->post('eid'));
Model Change:
$this->db->where('eid',$this->input->post($data))
$this->db->where('eid',$this->input->post('eid'));
修改你的更新功能,如下所示:
function update($id = 0){
$this->load->helper('form');
$this->load->helper('html');
$this->load->model('employees_model');
if($this->input->post('upsubmit')){
$id= $this->input->post('eid');
if($this->input->post('eid')){
$this->employees_model->entry_update();
}
}
$data = $this->employees_model->general();
if((int)$id > 0){
$query =this->employees_model->get($id);
$data['txt_id']['value'] = $query['eid'];
$data['txt_name']['value'] = $query['ename'];
$data['txt_salary']['value'] = $query['esalary'];
$data['txt_emailid']['value'] = $query['eemailid'];
}
$this->load->view('employees_update',$data);
}