在数据库中同时插入两个数据数组


Insert two arrays of data in the same time in a database

我有两个数组$fuel和$hours,具有相同数量的数据,我想在数据库中插入它们在同一时间。

我有:

$fuellength = count($fuel);
$f = 0;             
for($f=0;$f<$fuellength;$f++){ 
if ($fuel[$f] > 0){
    if (
    mysql_query("INSERT INTO grafiku (vehicle_plate, fuel_level, date_hour) VALUES (".$userid.", ".$hours[$f].",     '".$fuel[$f]."')");
        ) 
        echo "data has been inserted"; 
     else 
        echo "data has not been inserted";
 } //end if 
}//end for                      

它什么也没显示!对数组使用'for'循环是正确的吗?还是只使用foreach ?如果是这样,我怎么能循环抛出两个数组在同一时间??

提前感谢!最好的祝福

如果你的代码完全像这样,你将看不到任何东西,因为你有一个致命的php错误。你有一个ELSE语句,没有开始的IF语句。从你的IF语句中删除注释,它应该再次工作。

$fuellength = count($fuel);
$f = 0;             
for($f=0;$f<$fuellength;$f++){ 
if ($fuel[$f] > 0){
    $qryStr = "INSERT INTO grafiku (vehicle_plate, fuel_level, date_hour) VALUES (".$userid.", ".$hours[$f].",     '".$fuel[$f]."')";
    echo $qryStr."/br"; 
 } 
}

检查您是否正在获取查询和值

您的代码中有错误,解析错误:语法错误,&lt中的意外T_ELSE;文件名>第12行

<?php
   $fuellength = count($fuel);
   $f = 0;             
  for($f=0;$f<$fuellength;$f++){ 
  if ($fuel[$f] > 0){
  if (mysql_query("INSERT INTO grafiku (vehicle_plate, fuel_level, date_hour) VALUES     (".$userid.", ".$hours[$f].",     '".$fuel[$f]."')")) 
    echo "data has been inserted"; 
     else 
    echo "data has not been inserted";
 } //end if 
 }//end for
?>

假设您已经与MySQL服务器建立了连接:

$cn = mysql_connect("hostname", "username", "password");

假设您已经选择了数据库:

mysql_select_db("databasename", $cn);
你的逻辑是正确的。但是您的SQL插入顺序与您的字段不匹配。您正在尝试将$fuel[$f]数据插入date_hour字段。
$f = 0;
$added = 0; 
$noAdded = 0;             
while($f < count($fuel))
{ 
    if ($fuel[$f] > 0) 
    { 
        if(mysql_query("INSERT INTO grafiku 
                   (vehicle_plate,   fuel_level,    date_hour) 
            VALUES (".$userid.",   ".$fuel[$f].", '".$hours[$f]."')"
        ))
            $added++; 
        else 
            $noAdded++;
    }
    $f++;
}
//Then you can display additional information after inserting is done. 
echo $added . " data has been added to table.";
echo "<br />";
echo $noAdded . " data could not be added to table.";