我有一个类型为file (multiple)的html输入:
<input id="image" type="file" name="dog[]" multiple>
我怎么能上传他们与"图像"answers"狗"使用解析关系表解析?
或者有更好的存储关系的方法吗?请建议。由于
代码尝试:
<?php
require 'vendor/autoload.php';
session_start();
use Parse'ParseClient;
use Parse'ParseUser;
use Parse'ParseSessionStorage;
use Parse'ParseObject;
use Parse'ParseFile;
use Parse'ParseGeoPoint;
ParseClient::initialize('xxx', 'yyy', 'zzz');
ParseClient::setStorage(new ParseSessionStorage());
$currentUser = ParseUser::getCurrentUser();
$filearray = [];
$count = 0;
if (isset($_POST) and $_SERVER['REQUEST_METHOD'] == "POST") {
foreach ($_FILES['dog']['name'] as $f => $name) {
if ($_FILES['dog']['error'][$f] == 4) {
continue; // Skip file if any error found
}
if ($_FILES['dog']['error'][$f] == 0) {
$tmp = $_FILES['dog']['tmp_name'][$count];
$count = $count + 1;
$file = ParseFile::createFromData(file_get_contents($tmp), $_FILES['dog']['name']);
$file->save();
array_push($filearray, $file);
}
}
}
$dogobj = new ParseObject("Dog");
$dogobj->setArray("dogimage", $filearray);
try {
$dogobj->save();
} catch (ParseException $ex) {
echo 'Failed to create new object, with error message: ' . $ex->getMessage();
}
编辑::谢谢你的回复，这是我发现的错误
注意:在../index.php的第31行没有定义索引:restaurant_images
警告:第31行./index.php中为foreach()提供的参数无效用objecd: fz1hnCembE创建新对象
到第31行，它指向foreach ($_FILES['restaurant']['name'] as $f => $name) {
我保存的对象成功了，正如你在上面的消息中看到的，图像没有找到
确保表单具有值为multipart/form-data的属性enctype，否则超全局数组$_FILES将为空
<form action="" method="post" enctype="multipart/form-data">
<input id="image" type="file" name="dog[]" multiple>
<input type="submit"/>
</form>
<?php
if (isset($_FILES['dog']) === true) {
$dog = $_FILES['dog'];
$limit = count(current($dog));
for ($i = 0; $i < $limit; $i++) {
$error = $dog['error'][$i];
if ($error === UPLOAD_ERR_OK) {
$name = $dog['name'][$i];
$type = $dog['type'][$i];
$tmp_name = $dog['tmp_name'][$i];
$size = $dog['size'][$i];
//other code
}
}
}
?>