你好,我正在为自己开发一个项目。我要做的是验证所有调用api除了用户注册。我创建了用户认证和用户提供者,如下链接所述:http://symfony.com/doc/current/cookbook/security/api_key_authentication.html
一切都很好,所有的url到我的后端是经过身份验证的,它们是由UserTokenAuthenticator和UserTokenProvider处理的。但是它会验证每个电话。我不想验证这个url
/v1.0/users with POST method
所以我设置了安全访问控制。Yml文件如下:
access_control:
user_register:
path: ^/v1.0/users
roles: IS_AUTHENTICATED_ANONYMOUSLY
methods: [POST]
但是每当我尝试对这个url进行post调用时,它都会尝试进行身份验证(因为调用没有令牌作为参数)并且失败。如何防止只对这条路由进行认证??以下是我的全部代码:
security.yml:
security:
encoders:
entity_user:
class: KBell'AppBundle'Entity'User
algorithm: sha1
iterations: 1
encode_as_base64: false
entity_device:
class: KBell'AppBundle'Entity'Device
algorithm: sha1
iterations: 1
encode_as_base64: false
role_hierarchy:
ROLE_DEVICE: ROLE_DEVICE
ROLE_USER : ROLE_USER
providers:
entity_device:
entity:
class: KBell'AppBundle'Entity'Device
property: name
entity_user:
entity:
class: KBell'AppBundle'Entity'User
property: email
user_token_provider:
id: user_token_provider
firewalls:
dev:
pattern: ^/(_(profiler|wdt)|css|images|js)/
security: false
api_user_secured_area:
pattern: ^/v1.0/users
stateless: true
simple_preauth:
authenticator: user_token_authenticator
provider: user_token_provider
access_control:
user_register:
path: ^/v1.0/users
roles: IS_AUTHENTICATED_ANONYMOUSLY
methods: [POST]
这里是UserTokenAuthenticator:
<?php
class UserTokenAuthenticator implements SimplePreAuthenticatorInterface, AuthenticationFailureHandlerInterface
{
public function createToken(Request $request, $providerKey)
{
$accessToken = $request->query->get('access_token');
if (!$accessToken) {
throw new BadCredentialsException('Access Token is missing');
}
return new PreAuthenticatedToken(
'anon.',
$accessToken,
$providerKey
);
}
public function authenticateToken(TokenInterface $token, UserProviderInterface $userProvider, $providerKey)
{
$accessToken = $token->getCredentials();
$user = $userProvider->getUserForAccessToken($accessToken);
if (!$user) {
throw new AuthenticationException(
sprintf('Access Token "%s" does not exist.', $accessToken)
);
}
return new PreAuthenticatedToken(
$user,
$accessToken,
$providerKey,
$user->getRoles()
);
}
public function supportsToken(TokenInterface $token, $providerKey)
{
return $token instanceof PreAuthenticatedToken && $token->getProviderKey() === $providerKey;
}
public function onAuthenticationFailure(Request $request, AuthenticationException $exception)
{
return ApiUtil::getJsonErrorResponse("User authentication is failed: ".$exception->getMessage(), Response::HTTP_UNAUTHORIZED, "AuthenticationException");
}
}
UserTokenProvider.php:
class UserTokenProvider implements UserProviderInterface
{
private $userManager;
public function __construct(UserManager $userManager)
{
$this->userManager = $userManager;
}
public function getUserForAccessToken($accessToken)
{
$user = $this->userManager->findUserByAccessToken($accessToken);
return $user;
}
public function loadUserByUsername($username)
{
}
public function refreshUser(UserInterface $user)
{
throw new UnsupportedUserException();
}
public function supportsClass($class)
{
return 'Symfony'Component'Security'Core'User'User' === $class;
}
}
我为此花了很多时间。任何帮助将不胜感激!谢谢你!
我想你可以试着这样配置你的防火墙设置:
firewalls:
secured_user_area:
pattern: /v('d+'.?'d*)/(?!users)
stateless: true
provider: user_token_provider
....
这里?!users
(甚至多个url,如?!users|URL2|URL3
)声明排除防火墙中的url