<?php
$next_month = strtotime("+1 month");
//
$next_month_formatted = date("n", $next_month);
$link = "";
if(! empty($next_month_formatted))
switch($next_month_formatted % 5)
{
case '10':
$link = "https://rightsignature.com/forms/10-1-15-MCDONALDS-e13aff/token/da0d4ec67cf";
break;
case '11':
$link = "https://rightsignature.com/forms/11-1-15-MCDONALDS-a0a0ec/token/8232d7c2265";
break;
case '12':
$link = "https://rightsignature.com/forms/121-15-MCDONALDS--89d5a0/token/84b88a8c248";
break;
case '1':
$link = "https://rightsignature.com/forms/1-1-16-MCDONALDS--fa49d9/token/79dd025e3f1q";
break;
case '2':
$link = "https://rightsignature.com/forms/2-1-16-MCDONALDS--022aff/token/4bc0a37cf49";
break;
case '3':
$link = "https://rightsignature.com/forms/3-1-16-MCDONALDS--d1313d/token/47b351070c1";
break;
case '4':
$link = "https://rightsignature.com/forms/4-1-16-MCDONALDS--0cf9d2/token/bb31f6bb11e";
break;
case '5':
$link = "https://rightsignature.com/forms/5-1-16-MCDONALDS--37e75d/token/d1b044125f2";
break;
default:
$link = "#";
}
echo $next_month_formatted(10);
?>
我试图获得返回值,但我有一个错误的函数。我是新来的,所以我不能准确地描述它是什么。我正在根据数据范围更改日期。
我正在尝试回显当前月份。我试图反映十月的链接,这是案例10。
切换后,回显如下:
echo $next_month_formatted(10);
不应该回显$link吗?
echo $link;