如果找到Item，打印父节点的属性

如果找到Item，我想打印父节点属性。我正在使用XPath, PHP和XML。我的代码是

if( ! $xml = simplexml_load_file($my_feed) ) 
        { 
            echo 'unable to load XML file'; 
        } 
        else 
        { 
            $nodes = $xml->xpath("//Stock/Assortment[contains(translate(Item, 'АБВГДЕЁЖЗИЙКЛМНОПРСТУФХЦЧШЩЬЫЭЮЯ', 'абвгдеёжзиёклмнопрстуфхцчшщьыэюя'), '$search_phrase')]|/Stock/@City | /Stock/@CompanyName | /Stock/@Address | /Stock/@Date");
            foreach($nodes as $node)
            {
                if(strpos($node->Item,$search_phrase) !== false)
                {
                print $node->City.$node->CompanyName.$node->Address.$node->Date;
                }
                print $node->Item."'r'n".$node->Price."'r'n".$node->ValidDate."'r'n".$node->Manufacturer."'r'n"."<br/>";
            } 
        }

不打印父节点的属性，有什么问题吗?我的xml是:

<?xml version="1.0" encoding="utf-8"?>
<Stock City="Душанбе" CompanyName="Фирик и ко" Address="Ленина 2" Date="12.06.2014 06:22:58">
  <Assortment>
    <ID>1</ID>
    <Item>3В амп.  №3 ( Витамины В1+В6+В12 )</Item>
    <Quantity>8</Quantity>
    <Price>17.0000</Price>
    <ValidDate>01.01.1999</ValidDate>
    <Summ>136.0000</Summ>
    <Manufacturer>Заглушка</Manufacturer>
    <Supplier>Заглушка</Supplier>
  </Assortment>
</Stock>