我正在做一个chrome扩展(freshment),有一个小问题。
我有一个按钮,我想当按钮被点击,显示我的信息从我的数据库在我的扩展页。
<button class="button" id="show" style="vertical-align:middle" onclick="myAjax()"><span>Show my purchaes</span></button>
<div id="showhere">
//this is where i want to show the info
</div>
Java Script:
$(document).ready(function(){
function myAjax() {
$.ajax({
url:"http://127.0.0.1/show.php",
data:{ action:'showhere' },
method:"POST",
success:function(data) {
('#showhere').html(data);
}
});
}
});
PHP: <?php
if($_POST['action'] == 'showhere') {
$servername = "localhost";
$username = "root";
$password = "********";
$dbname = "test";
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT ProductName, Amount, Date, WebStore FROM budget";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo "<table><tr><th>ID</th><th>Name</th></tr>";
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<tr><td>".$row["ProductName"]."</td><td>".$row["Amount"]."</td><td>".$row["Date"]."</td><td>".$row["WebStore"]."</td></tr>";
}
echo "</table>";
} else {
echo "0 results";
}
$conn->close();
}
?>
我想要它做的很简单:我有一个按钮,下面我有一个div叫做:"showhere",在这个div中我想把mysql信息写下来。我没有写出确切的问题,问题是按钮不做任何事情。
再来一次,谢谢!我建议你这样设置:
$(document).ready(function() {
$('#show').on('click', function(e) {
e.preventDefault();
$.ajax({
url: "http://127.0.0.1/show.php",
data: {
action: 'showhere'
},
method: "POST",
success: function(data) {
('#showhere').html(data);
}
});
});
});