查询id为mongoID的集合 - Querying a collection with an array of mongoID

Querying a collection with an array of mongoID

本文关键字：集合 mongoID id 查询 | 更新日期: 2023-09-27

我有以下代码:

// company_ids is an array of mongo IDs
// company_id is an array (with only 1 element) of mongo ID
foreach($company_ids as $company_id){
    $results = Archive::where("billing.company._id", 'all', array($company_id))->get();
    ...

这是Log::info(print_r($company_ids, true))

的输出

[2016-10-22 02:41:27] production.INFO: Array
(
    [0] => 57515764b91a8c4d008b45d1
    [1] => 57515764b91a8c4d008b45d6
    [2] => 57515764b91a8c4d008b45db
    [3] => 57515764b91a8c4d008b45e0
    ...
)

如何使用company_ids直接查询Archive收集，而不需要foreach循环?

@Robbie答案的小更新。不需要使用MongoIds的数组，只需使用字符串数组就可以了。我只使用larvel -jenessenger

$company_ids = [
    '57515764b91a8c4d008b45d1',
    '57515764b91a8c4d008b45d6',
    '57515764b91a8c4d008b45db',
    '57515764b91a8c4d008b45e0'
]
$results = Archive::whereIn('billing.company._id', $company_ids)->get();

根据库的自述文件:

$results = Archive::whereIn('billing.company._id', $company_ids)->get();

(我不清楚数组$company_ids是什么，但我认为它需要是和MongoID数组:但这也取决于你正在使用的底层库，Mongo或MongoDB，因为两者都由库支持)

$company_ids = [
    new mongoID('57515764b91a8c4d008b45d1'),
    new mongoID('57515764b91a8c4d008b45d6'),
    new mongoID('57515764b91a8c4d008b45db'),
    new mongoID('57515764b91a8c4d008b45e0'),
]