使用关联数组替换字符串中的几个单词,保持原始大小写不变


Replace several words in string using associative array keeping original case intact

我想将一个数组与一个文本字符串进行匹配,其中与数组键匹配的单词将被一个带有匹配数组值的标题的span标记所替换。

我可以用str_ireplace这样做,但是匹配的单词会丢失大小写:

$glossary = array(
    'word1' => '<span title="Explanation for Word 1">word1</span>',
    'word2' => '<span title="Explanation for Word 2">word2</span>',
    'word3' => '<span title="Explanation for Word 3">word3</span>'
);
$text = "This is a text about Word1. We also talk about word2 and WORD3. Also woRd3, word2 and WORD1";
list($keys, $values) = array_divide($glossary);
$result = str_ireplace($keys, $values, $text);

如前所述,这是有效的,但在这个解决方案中,所有匹配的单词都将是小写的。

我想实现的是:

'This is a text about <span title="Explanation for Word 1">Word1</span>. 
We also talk about <span title="Explanation for Word 2">word2</span> and
<span title="Explanation for Word 3">WORD3</span>.
Also <span title="Explanation for Word 3">woRd3</span>, 
<span title="Explanation for Word 2">word2</span>
and <span title="Explanation for Word 1">WORD1</span>'

进行替换,保持箱子完整

我发现了一个很好的回复,接近但它只适用于在匹配的单词周围添加span标签,它不为标题添加第二个变量(php str_ireplace而不丢失大小写)。

我不知道足够的正则表达式(它让我眼花缭乱)通过为span标题添加第二个变量来改变它:

$txt = 'Hi! How are you doing? Have some stars: * * *!';
$array_of_words = array('Hi!', 'stars', '*');
$pattern = '#(?<=^|'W)(' 
       . implode('|', array_map('preg_quote', $array_of_words))
       . ')(?=$|'W)#i';
echo preg_replace($pattern, 
      "<span style='background-color:#EEEE00'>$1</span>", $txt);

你可以运行这个replace in循环:

$txt = 'Hi! How are you doing? Have some stars: * * *!';
$glossary = array(
    'Hi!'   => 'title 1',
    'stars' => 'title 2',
    '*'     => 'title 3'
);
$result = $txt;
foreach ($glossary as $keyword => $title) {
    $pattern = '#(?<=^|'W)('.preg_quote($keyword).')(?=$|'W)#i';
    $result  = preg_replace($pattern, "<span title='{$title}'>$1</span>", $result);
}
echo $result;

您可以使用一些常见的PHP函数来实现。

  1. keys中创建一个模式数组,以不区分大小写的方式使用preg_replace_callback进行搜索。

  2. $glossary传递给preg_replace_callback中的匿名函数,通过小写的当前匹配值获得值(<span>标题),一旦找到,将小写的wordX替换为匹配。

这是PHP代码:
$pttrns = array_map(function ($val) {return "/" . preg_quote($val) . "/i"; },
                  array_keys($glossary));                                    // Step 1
$res = preg_replace_callback($pttrns, function ($m) use($glossary){          // Step 2
    return str_replace(strtolower($m[0]), $m[0],              
                                     $glossary[strtolower($m[0])]);         // Step 3
}, $text);