页面中有一个按钮。在点击按钮,它应该去另一个页面,该页面应该被查看。此外,我想传递一些值到第二页时,按钮被单击,并在第二页中显示传递的值。
我写了一个代码在ajax,但它不工作。
<script>
$(document).ready(function(){
$(".chk").click(function(){
if($('input.checkin:checked').val()){
var apikey = '60CF3C2oh7D+Q+aHDoHt88aEdfdflIjFZdlmsgApfpvg8GXu+W8qr7bKM33cM3';
var password = 'fHdfvxk';
var endpoint = 1;
var method = 'ProcessPayment';
var dataString = 'APIKey='+apikey+'&APIPassword='+password+'&ddlSandbox='+endpoint+'&ddlMethod='+endpoint;
$.ajax({
type: "POST",
url: "responsive.php",
data: dataString,
cache: false,
success: function(result){
}
});
//window.location.href= 'http://localhost/m/responsive.php';
}
else{
alert("Please Accept the terms and conditions and continue further!!!!");
}
}); });
</script>
我写了一个代码在ajx当按钮单击,但它只会传递值到该页。但是页面无法查看。有谁能提出一个解决方案吗?
您可以重定向到页面,而不是使用ajax。
<script>
$(document).ready(function(){
$(".chk").click(function(){
if($('input.checkin:checked').val()){
var apikey = '60CF3C2oh7D+Q+aHDoHt88aEdfdflIjFZdlmsgApfpvg8GXu+W8qr7bKM33cM3';
var password = 'fHdfvxk';
var endpoint = 1;
var method = 'ProcessPayment';
//var dataString = 'APIKey='+apikey+'&APIPassword='+password+'&ddlSandbox='+endpoint+'&ddlMethod='+endpoint;
// use location href instead of ajax
window.location.href = "responsive.php?APIKey='+apikey+'&APIPassword='+password+'&ddlSandbox='+endpoint+'&ddlMethod='+endpoint;
}
else{
alert("Please Accept the terms and conditions and continue further!!!!");
}
});
});
</script>