目前我们有两个表。位置和地址
地址和address .location_id上的地址是一对多的关系。
我们正在尝试输出与cgridview中特定位置相关的所有地址:
admin.php
<?php $this->widget('zii.widgets.grid.CGridView', array(
'id'=>'locations-grid',
'dataProvider'=>$location->search(),
'filter'=>$location,
'columns'=>array(
'id',
'name',
array(
'name' => 'address',
'value' => 'implode("<br>",CHtml::listData($data->addresses(),"id","address"))',
'filter' => CHtml::activeTextField($location, 'address'),
'type' => 'html',
),/**/
array(
'class'=>'CButtonColumn',
),
),
)); ?>
模型(locations.php)
public function search()
{
// Warning: Please modify the following code to remove attributes that
// should not be searched.
$criteria=new CDbCriteria;
$criteria->together = true;
$criteria->with = array('addresses');
$criteria->compare('id',$this->id);
$criteria->compare('name',$this->name,true);
$criteria->compare('addresses.address',$this->address,true);
return new CActiveDataProvider($this, array(
'criteria'=>$criteria,
));
}
是否有更好的方法来获取地址数据，而不是内爆$data->地址函数?
你可以给你的Locations模型添加一个getter方法。
public function getAddressNames($separator='<br>')
{
$names = array();
foreach($this->adresses as $address) {
$names[] = $address->address;
}
return implode($separator, $names);
}
然后你可以使用addressNames像一个常规属性在你的gridview