我需要有一个搜索与两个下拉框使用ajax执行。我的主文件是
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function () {
$("#display").hide();
var country ="";
var option = "";
$(".selectpicker").on('change', function () {
option=$(this).val();
myCall(option,country)
});
$(".bfh-selectbox-filter").on('blur', function () {
country=$(this).val();
myCall(option,country)
});
});
function myCall(option,country){
if (country.length > 0 && option.length > 0) {
$.ajax({
type: "POST",
url: "search.php",
data: {country: country, option:option},
success: function (data) {
$("#display").html(data).show();
}
});
}
else {
$("#display").html('please select both the fields').show();
}
}
<div class="col-md-5 col-sm-5">
<select class="form-control selectpicker" required>
<option value="">Select Option</option>
<option value="Batsman">Batsman</option>
<option value="Bowler">Bowler</option>
<option value="AllRounder">All rounder</option>
<option value="Wicket Keeper">Wicket Keeper</option>
</select>
<script>
$(document).ready(function(e) {
$(document).find(".bfh-countries input[type=hidden]").attr("name","country");
});
这是我的search.php代码。我需要的结果显示后,搜索按钮单击。结果必须与这两个下拉框的选择组合在一起显示。
if (isset($_POST['country']) && isset($_POST['option'])) {
$country = trim($_POST['country']);
$option = trim($_POST['option']);
$query2 = mysql_query("SELECT * FROM tbl_users INNER JOIN tbl_cricketerattr on users_id = tbl_users_users_id WHERE country='$keyword' and option='$option'");
$result= "<ul id='playerlist'>";
while ($query3 = mysql_fetch_array($query2)) {
$result.= "<li id='list' onclick='fill()'>". $query3['first_name'].":". $query3['country']."</li>";
}
$result.= "</ul>";
echo $result;}
请帮助! !
试试这样添加一个搜索按钮来执行搜索。如果不需要,可以使用change event。
你的html和脚本:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function () {
$("#display").hide();
var country ="";
var option = "";
$(".selectpicker").on('change', function () {
option=$(this).val();
myCall(option,country)
});
$("ul li a").on('click', function () {
country=$(this).data("option");
myCall(option,country)
});
});
function myCall(option,country){
console.log(option+":"+country);
if (country.length > 0 && option.length > 0) {
$("#display").html("");
$.ajax({
type: "POST",
url: "search.php",
data: {country: country, option:option},
success: function (data) {
$("#display").html(data).show();
}
});
}
else {
$("#display").html('please select both the fields').show();
}
}
</script>
<div class="col-md-5 col-sm-5">
<select class="form-control selectpicker" required>
<option value="">Select Option</option>
<option value="Batsman">Batsman</option>
<option value="Bowler">Bowler</option>
<option value="AllRounder">All rounder</option>
<option value="Wicket Keeper">Wicket Keeper</option>
</select>
</div>
<div class="col-md-3 col-sm-3">
<div class="bfh-selectbox bfh-countries" data-country="US" data-flags="true">
<input type="hidden" value="">
<a class="bfh-selectbox-toggle" role="button" data-toggle="bfh-selectbox" href="#">
<span class="bfh-selectbox-option input-medium" data-option=""></span>
<b class="caret"></b>
</a>
<div class="bfh-selectbox-options">
<input type="text" class="bfh-selectbox-filter">
<div role="listbox">
<ul role="option">
</ul>
</div>
</div>
</div>
</div>
<div id="display"></div>
your search.php:我还没有测试过,如果有任何问题请随时询问。
<?php
include('includes/db.php');
if (isset($_POST['country']) && isset($_POST['option'])) {
$country = trim($_POST['country']);
$option = trim($_POST['option']);
$query2 = mysql_query("SELECT * FROM tbl_users INNER JOIN tbl_cricketerattr on users_id = tbl_users_users_id WHERE country='$keyword' and option='$option'");
$result= "<ul id='playerlist'>";
while ($query3 = mysql_fetch_array($query2)) {
$result.= "<li id='list' onclick='fill()'>". $query3['first_name'].":". $query3['country']."</li>";
}
$result.= "</ul>";
echo $result;
}
对于下拉搜索,您应该使用onchange()
事件进行搜索,如下所示
$(document).on("change","id or class of first dropdown",function () {
var keyword = $(this).val();
$.ajax({
type: "POST",
url: "search.php",
data: "keyword=" + keyword,
success: function (html) {
$("id or class of second dropdown").html(html).show();
}
});
});
如果我理解正确,你正试图使用ajax与两个下拉选项!
试试这样写:
$(document).ready(function () {
var country = $('.bfh-selectbox-filter').val();
var option = $('.selectpicker').val();
$(".selectpicker .bfh-selectbox-filter").on ('change', function () {
if (country !== '' && option !== '') {
$.ajax({
type: "POST",
url: "search.php",
data: ["country": country, "option":option],
success: function (html) {
$("#display").html(html).show();
}
});
}
else {
$("#display").html('please select both the drop downs').show();
}
});
});