我想在给定字符串中包装一些gmail地址的html元素。如何使用php regex.
输入$string = 'Sample text name@gmail.com another text name2@gmail.com,name2@yahoo.com';
输出
$string = "Sample text <div class='gmail'>name@gmail.com</div> another text <div class='gmail'>name2@gmail.com</div>,name2@yahoo.com";
试试这样写:
$string = 'Sample text name@gmail.com another text name2@gmail.com,name2@yahoo.com';
echo preg_replace("/(['._a-zA-Z0-9-]+@['._a-zA-Z0-9-])+/i", "<div class='gmail'>$1</div>", $string);
Gmail只:
$string = 'Sample text name@gmail.com another text name2@gmail.com,name2@yahoo.com';
echo preg_replace("/(['._a-zA-Z0-9-]+@gmail.com)+/i", "<div class='gmail'>$1</div>", $string);
您几乎可以采用任何电子邮件搜索正则表达式，只需将域名部分替换为固定字符串。然后搜索和替换不需要太多的努力:
= preg_replace('/'b'w['w+.%!-]+@gmail.com'b/', "<div class=gmail>$0</div>", $src);
# ^^^ allowed special chars still insufficient
preg_replace('('w+?@'w+?'.'w+)', '<div class="gmail">$0</div>', 'Sample text name@gmail.com another text name2@gmail.com,name2@yahoo.com');