我有一个问题,将数据从cookie存储到html值字段。我正在用php生成html。
代码: $cookieName = $_COOKIE["username"];
$cookiePass = $_COOKIE["password"];
if(isset($_COOKIE['username']) && isset($_COOKIE['password'])){
echo "<input type='text' name='name' value='echo $cookieName'>";
echo "<input type='password' name='pass' value= 'echo $cookiePass'>";
}else{
echo "<input type='text' name='name'>";
echo "<input type='password' name='pass'>";
}
输出变量错误
代替if(isset($_COOKIE['username']) && isset($_COOKIE['password'])){
echo "<input type='text' name='name' value='echo $cookieName'>";
echo "<input type='password' name='pass' value= 'echo $cookiePass'>";
}
if(isset($_COOKIE['username']) && isset($_COOKIE['password'])){
echo "<input type='text' name='name' value='{$cookieName}'>";
echo "<input type='password' name='pass' value= '{$cookiePass}'>";
}
您在echo
中使用echo
语法错误。应该将字符串和变量连接起来,而不是两次使用echo,其间不使用分号。我建议用引号把双引号反开。只需更改为
echo '<input type="text" name="name" value="'. $cookieName.'">';
echo '<input type="password" name="pass" value= "'. $cookiePass.'">';
这样做
echo "<input type='text' name='name' value='".$cookieName."'>";
echo "<input type='password' name='pass' value= '".$cookiePass."'>";
而不是-
echo "<input type='text' name='name' value='echo $cookieName'>";
echo "<input type='password' name='pass' value= 'echo $cookiePass'>";
只管做
echo "<input type='text' name='name' value='" . $cookieName . "'>";
你不能在字符串中使用PHP的echo函数。因此,解决方案就是将字符串与参数组合在一起。
第二种方法是像这样使用{$var}:echo "<input type='text' name='name' value='{$cookieName}'>";
$cookieName = $_COOKIE["username"];
$cookiePass = $_COOKIE["password"];
if(isset($_COOKIE['username']) && isset($_COOKIE['password'])){
echo "<input type='"text'" name='"name'" value='"{$cookieName}'">";
echo "<input type='"password'" name='"pass'" value='"{$cookiePass'">";
} else{
echo "<input type='text' name='name'>";
echo "<input type='password' name='pass'>";
}