我必须使用Ajax调用制作幻灯片(我已经通过更改左距来完成,但现在我需要这样做)。我有一个php数组,我从数据库拉。我需要用这个来显示图像。很抱歉,我不能对这个问题进行更深入的讨论,如有任何指导,我将不胜感激。
PHP/HTML$pic_array = array();
$titles = array();
$descriptions = array();
while ($row = $result->fetch_assoc()) {
$pic_array[$count] = $row['pic_url'];
$titles[$count] = $row['title'];
$descriptions[$count] = $row['description'];
$count++;
}
echo "<input id='json_pics' type='hidden' value='" . json_encode($pic_array) . "'/>";
echo "<input id='titles' type='hidden' value='" . json_encode($titles) . "'/>";
echo "<input id='descriptions' type='hidden' value='" . json_encode($descriptions) . "'/>";
echo "<div id='slider'>
<ul class='slides'>
<li class='slide'>
<div class='pic'>
<img src= " . $dir . $pic_array[$x] . " />
</div>
<div class='caption'>
<p id='title'>$titles[$x]</p>
<p id='des'>$descriptions[$x]</p>
</div>
<div class='next'>
<i class='fa fa-arrow-right fa-2x'></i>
</div>
<div class='previous'>
<i class='fa fa-arrow-left fa-2x'></i>
</div>
</li>";
echo "</ul>
</div>
</html>";
$conn->close();
?>
Javascript /**
* Created by daneh_000 on 6/27/2016.
*/
$(function () {
var arrPix = $('#json_pics').val();
var arrPix = $.parseJSON( arrPix );
var width = 450;
var slide_number = 1;
var $slider = $('#slider');
var $slides = $slider.find('.slides');
var $slide = $slides.find('.slide');
var $next = $slides.find('.next');
var $previous = $slides.find('.previous');
var $caption = $slides.find('.caption');
var slide_length = $slide.length;
$slider.hover(function() {
$caption.css('opacity', '1');
$next.css('opacity', '1');
$previous.css('opacity', '1');
}, function() {
$caption.css('opacity', '0');
$next.css('opacity', '0');
$previous.css('opacity', '0');
}
);
$next.click(function() {
var xhttp = new XMLHttpRequest();
xhttp.onreadystatechange = function () {
if (xhttp.readyState == 4 && xhttp.status == 200) {
}
}
xhttp.open("POST", 'index.php', true);
xhttp.send("index= slide_number");
});
});
如果您只需要ajax滑块:您不需要自己编写它。你可以选择任何流行的滑块,例如http://bxslider.com和钩子slideChange(你可以在每个滑块中这样做)。例如:
$('ul.slides').bxSlider({
pager: true,
adaptiveHeight: true,
infiniteLoop: true,
onSlideBefore: function(slideElement, oldIndex, nextIndex) {
$.get('/url/to/slide/' + nextIndex /*or slideElement.attr('slide-get-url') for example*/ ,
function(response) {
slideElement.html(response);
}
);
}
});
如果你想写你自己的滑块-第一规则:它必须是独立的后端。Ajax请求必须返回一个(或多个)幻灯片的内部内容。不是外。JS只需要设置现有幻灯片(LI)的内容,或者在必要时创建更多的幻灯片。